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Masja [62]
3 years ago
5

How many different combinations of pennies, nickels, dimes, quarters, and half dollars can a piggy bank contain if it has 23 coi

ns in it
Mathematics
1 answer:
muminat3 years ago
5 0

Answer:

C ( 27, 4 )  number of ways

Step-by-step explanation:

number of coins in piggy bank = 23

x1 = number of pennies

x2 = number of nickels

x3 = number of dimes

x4 = number of quarters

x5 = number of half dollars

The required condition = 23

The required different combinations can be represented as

=  C ( 5 + 23 - 1 , 23 ) = C ( 27 , 23 )

                                  = C ( 27, 4 )

This is because :( C ( n, r ) = C (n, n-r ))

         

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I need this Now (2x + 1)²
Alla [95]

Answer:

4x² + 4x + 1

Step-by-step explanation:

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Pls answer this i need help
Vitek1552 [10]

Step-by-step explanation:

your don't see what went wrong ?

Tyrell worked on

16 - 2(4 + 3x)

what do brackets mean ? they mean that this operation has to be done before everything else in the expression.

as this contains a variable, we cannot fully calculate it, true, but we need to keep this in mind and always treat the content of the brackets as one package.

so, whatever I do from the outside with one part of that package, I have to do also with all the other parts of that package.

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therefore, the correct simplification looks like

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Amelia multiplied correctly, but then made a mistake summing things up

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I can't mix the pure constant -3 into the factors of x. that would be like the famous mixing of apples and oranges.

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6 0
2 years ago
Create an equivalent expression using the drop downs below 4(32 – 4).
GaryK [48]

Answer:

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Step-by-step explanation:

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3 0
2 years ago
I need help
dangina [55]

Answer:

a)  x =3 and x=5

c)  x =-1 and x = \frac{-7}{3}

i)  x =0 and  x = \frac{-9}{2}

Step-by-step explanation:

a)

Given that the quadratic equation

    x² - 8x +15 =0

The factors of 15 = 5 × 3

   x² - 5x -3x +15 =0

  x(x -5) -3(x-5) =0

  (x-3)(x-5) =0

x =3 and x=5

c)

  3 x² + 10 x +7 =0

⇒   3x² + 3x + 7x +7 =0

⇒   3x (x +1) +7(x+1) =0

⇒  (x+1) ( 3 x +7) =0

⇒  x =-1 and x = \frac{-7}{3}

i)

     2 x ² + 9 x =0

⇒ x( 2 x + 9) =0

⇒ x =0 and 2 x = -9

⇒ x =0 and  x = \frac{-9}{2}

4 0
3 years ago
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