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Masja [62]
3 years ago
5

How many different combinations of pennies, nickels, dimes, quarters, and half dollars can a piggy bank contain if it has 23 coi

ns in it
Mathematics
1 answer:
muminat3 years ago
5 0

Answer:

C ( 27, 4 )  number of ways

Step-by-step explanation:

number of coins in piggy bank = 23

x1 = number of pennies

x2 = number of nickels

x3 = number of dimes

x4 = number of quarters

x5 = number of half dollars

The required condition = 23

The required different combinations can be represented as

=  C ( 5 + 23 - 1 , 23 ) = C ( 27 , 23 )

                                  = C ( 27, 4 )

This is because :( C ( n, r ) = C (n, n-r ))

         

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Step-by-step explanation:

Statement. Reason

→ 9(x-6)+41 = 75. Transposing the like terms.

→ 9(x-6) = 75 - 41 Performing subtraction of the term in RHS

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→ 9x - 54 = 34 Distributive property

→ 9x = 34 + 54 Performing addition of the term in RHS.

→ 9x = 88. Now, transpose 9 from LHS to RHS , it's arthmetic operator will get changed.

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2 years ago
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B- using the formula from A

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3 years ago
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kondaur [170]
If by decomposition you mean breaking it ino parts then

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should be same as other sinces same base (y) and same height (h)
15

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8 0
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Liula [17]

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Step-by-step explanation:

I guessed and it was right

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