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Mnenie [13.5K]
3 years ago
10

The sum of the angles of a triangle is 180 degrees. If one of the acute angles of a right triangle is 52 degrees, what is the me

asure of the other acute angle? A: Let x be the measure of the unknown acute angle. Write an equation relating this measure to the known quantities. Do not include units in your equation.
Mathematics
1 answer:
Arada [10]3 years ago
4 0

Answer:

An equation is x+52\°+90\°=180\°

Step-by-step explanation:

Let x be the measure of the unknown acute angle.

According to angle sum property of a triangle, sum of all the angles of a triangle is equal to 180°.

One of the acute angles of a right triangle is equal to 52°.

Also, the triangle is a right angled triangle, one of the angle must be equal to 90°.

x+52\°+90\°=180\°\\x+142\°=180\°\\x=38\°

So, an equation is x+52\°+90\°=180\°

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Chef Andy needed to adapt his recipes for his European kitchen staff in Paris. He was​ 1-pound portions of​ entrecote, 2 ounces
Ronch [10]

Answer:

1 pound = 0.454 kilograms

1 ounce = 0.0296 liters

1 ounce = 0.0283 kilograms

Step-by-step explanation:

You need to convert the quantities to their corresponding unit.

Convert pounds to kilograms (For the entrecote)

1 pound = 0.454 kilograms

Thus, 1 pound of entrecote = 0.454 kilograms

Ounces to liters (for the Béarnaise, since it is a liquid)

1 ounce = 0.0296 liters

2 ounces of Béarnaise = 0.0592 liters

Ounces to kilograms (for the asparagus)

1 ounce = 0.0283 kilograms

4 ounces of asparagus =0.1132 kilograms

8 0
3 years ago
What is the value of X?<br> A. 5<br> B. 2.5<br> C.7.5<br> D. 10
gizmo_the_mogwai [7]

10 is the value of x

3 0
3 years ago
Which inequality is graphed on the number line shown?
bearhunter [10]
The graph is to the left of -3, so it's < or ≤.
The circle is filled in so -3 also satisfies the inequality, so it's ≤.
The answer is B. x≤-3.
4 0
3 years ago
Center: (10,-10)
vova2212 [387]

This is the standard form equation \frac{(x - 10)^2}{100} + \frac{(y + 10)^2}{-100} = 1

What is the ellipse?

The equation for an ellipse is typically written as x² a²  + y² b² = 1. x²  a² + y² b²  = 1. An ellipse with its origin at the center is defined by this equation. The ellipse is stretched further in both the horizontal and vertical directions if a > b, a > b, and if b > a, b > a, respectively.

The standard form of the equation of an ellipse with center (h, k)and major axis parallel to the x-axis is:

\frac{(x - h)^2}{a^2} + \frac{(y - k)^2}{b^2} = 1

where,

a > b

the length of the major axis is 2a

the coordinates of the vertices are (h±a,k)

the length of the minor axis is 2b

the coordinates of the co-vertices are (h,k±b)

the coordinates of the foci are (h±c,k),

where c² = a² − b².

so,

\frac{(x - 10)^2}{100} + \frac{(y + 10)^2}{-100} = 1

Hence, this is the standard form equation \frac{(x - 10)^2}{100} + \frac{(y + 10)^2}{-100} = 1.

To learn more about ellipse, visit

brainly.com/question/16904744

#SPJ1

7 0
11 months ago
The populations of termites and spiders in a certain house are growing exponentially. The house contains 120 termites the day yo
zysi [14]

Answer:

in order to triple the inicial population of spiders, will take 50395 days

Step-by-step explanation:

we can define the termite population function as T(t) and the one for spiders as S(t) , where t represents time measured in days

since both have and exponencial growth

T(t)= a*e^(b*t)

S(t)= c*e^(d*t)

1) when the day the person moves in , t=0 and T(0)= 120 termites

T(0) = a*e^(b*0) = a = 120

2) after 4 days , t=4 and  the house contains T(4) = 210 termites

T(4)= 120*e^(b*4) = 210 → 4*b = ln (210/120) → b = (1/4)* ln(210/120)= 0.14

therefore

T(t) = 120*e^(0.14*t)

3) 3 days after moving in , t=3, there were T(3) = 120*e^(0.14*3)=182.63≈ 182 termites . The number of spiders is half of the number of termites → S(3) = T(3) * 1 spider/ 2 termites  =91.31 spiders ≈ 91 spiders

4) after 8 days of moving in , t=8, there were T(8) = 120*e^(0.14*8)=367.78≈ 368 termites . The number of spiders is 0.25 times the number of termites → S(8) = T(8) * 1 spider/ 4 termites =91.94 spiders   ≈ 92 spiders

from

S(t)= c*e^(d*t) → d = ln [S (tb)/S (ta) ] / (tb-ta)

therefore d = ln [ S(8)/S(3) ] / (8 - 3 ) = 2.18*10^-5

in order to triple the initial population

S(t3) = 3 *S(0) = 3*[c*e^(d*0)] = 3*c

S(t3) = c*e^(d*t3) = 3* c → t3 = ln(3) / d = 50395 days

5 0
3 years ago
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