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3 years ago

10

What is the solution set to the equation (3x+4)^2=7

1 answer:

Elina [12.6K]3 years ago

8 0

Answer:

Check the image below

Step-by-step explanation:

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This is complicated- what is 3x + (-2x)?

allochka39001 [22]

3x + (-2x) would be just subtracting 2x from 3x, so it would be 1x or x. Hope this helped<3

6 0

3 years ago

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Enter the expression N0e−λt, where N0 is N-naught (an N with a subscript zero) and λ is the lowercase Greek letter lambda.

Natali5045456 [20]

So the question tells to express the expression in your problem where N0 is N-naught and the symbol represent the lower case Greek letter lambda. So the best answer or expression would be that the lambda is the wavelength of the expression. I hope you are satisfied with my answer

7 0

3 years ago

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The sum of 2 times a number and 8 is 7

My name is Ann [436]

Answer:

The number is -1/2

Step-by-step explanation:

Let x be the number

2x+8 = 7

Subtract 8 from each side

2x+8-8 = 7-8

2x = -1

Divide each side by 2

2x/2 =-1/2

x = -1/2

The number is -1/2

8 0

3 years ago

Read 2 more answers

Security A rounds every 2 minutes and 20 seconds in the gate 1. Security B rounds every 1 minute and 40 seconds in the gate 2. I

Elden [556K]

Answer:

$Time = 11\frac{2}{3}\ min$

Step-by-step explanation:

Given

$Security\ A = 2\ mins, 20\ secs$

$Security\ B = 1\ mins, 40\ secs$

Required

After how many minutes, will they round together

First, convert the given time to minutes

$Security\ A = 2\ mins, 20\ secs$

$Security\ A = 2\ mins+ 20\ secs$

$Security\ A = 2\ mins+ \frac{20}{60}\ min$

$Security\ A = 2\ mins+ \frac{1}{3}\ min$

$Security\ A = 2\frac{1}{3}\ min$

$Security\ B = 1\ mins, 40\ secs$

$Security\ B = 1\ mins+ 40\ secs$

$Security\ B = 1\ mins+ \frac{40}{60}\ min$

$Security\ B = 1\frac{2}{3}\ min$

So, we have:

$Security\ A = 2\frac{1}{3}\ min$

$Security\ B = 1\frac{2}{3}\ min$

List out the multiples of the time of both security personnel take round.

$Security\ A = 2\frac{1}{3}min,\ 4\frac{2}{3}min,\ 7min,\ 9\frac{1}{3}min,\ 11\frac{2}{3}min...$

$Security\ B = 1\frac{2}{3}min,\ 3\frac{1}{3}min,\ 5min,\ 6\frac{2}{3}min,\ 8\frac{1}{3}min,\ 10min\ ,11\frac{2}{3}min,...$

In the above lists, the common time is:

$Time = 11\frac{2}{3}\ min$

<em>This implies that they go on round after </em> $11\frac{2}{3}\ min$ <em></em>

4 0

3 years ago

****ASAP*****<br> can someone pls help me with this? and can you describe it please?

Studentka2010 [4]

Add 165 to 245. That is a total of 410kWh.

245kWh is more than 50% of 410kWh.

So, according to the plan, you will pay NightTimer rate for kWh at night and DayTimer rate during the day.

The work done:

$(165*0.05281)+(245*0.05456)\\8.71365+13.3674=22.08085$

The raw, accurate, answer is that the value to pay is $22.08085.

In real terms, it is closer to your $22.08 option. That is the one I'd take.

5 0

3 years ago