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lbvjy [14]
4 years ago
8

When the whole is the same, why does it take 4 copies of 1 tenth to equal 2 copies of 1 fifth?

Mathematics
1 answer:
vaieri [72.5K]4 years ago
6 0
Because you can split the same whole into different parts. You can split a cake into 10 peices and eat 4 peices of the cake. That would be eating 4/10 of a cake. That would equal eating the same amount of cake if you split the cake into 5 peices and ate 2 of them.
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Factored 8x2y3-5= <br> I need the answer
ANTONII [103]

Answer: Reformatting the input :

Changes made to your input should not affect the solution:

(1): "y3" was replaced by "y^3". 1 more similar replacement(s).

STEP

1

:

Equation at the end of step 1

(23x2 • y3) - 5

STEP

2

:

Trying to factor as a Difference of Cubes

2.1 Factoring: 8x2y3-5

Theory : A difference of two perfect cubes, a3 - b3 can be factored into

(a-b) • (a2 +ab +b2)

Proof : (a-b)•(a2+ab+b2) =

a3+a2b+ab2-ba2-b2a-b3 =

a3+(a2b-ba2)+(ab2-b2a)-b3 =

a3+0+0+b3 =

a3+b3

Check : 8 is the cube of 2

Check : 5 is not a cube !!

Ruling : Binomial can not be factored as the difference of two perfect cubes

Final result :

8x2y3 - 5

5 0
3 years ago
Solve this <br> |2x-2|+6b
Anna71 [15]

Answer:

Step-by-step explanation:

its not letting me put the resolts but you can use this link and i hope it helps you :)

https://mathsolver.microsoft.com/en/solve-problem/%7C%202x-2%20%20%7C%20%20%2B6

6 0
3 years ago
A rectangular patio has a length of 12 1\2 feet and an area of 103 1\8 square feet. What is the width of the patio?
Whitepunk [10]

Answer:

8.25 feet

Step-by-step explanation:

to find the width, you divide the area by the length

103 1/8 / 12 1/2 = 8.25

Give brainliest, please!
Hope this helps :)

8 0
2 years ago
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Neporo4naja [7]

Hello!

Ill make this quick. The Fire house is in the third quadrant.

Hopefully this helps :)

4 0
3 years ago
Find the exact values of a) sec of theta b)tan of theta if cos of theta= -4/5 and sin&lt;0
Gre4nikov [31]

Answer:

Using trigonometric ratio:

\sec \theta = \frac{1}{\cos \theta}

\tan \theta = \frac{\sin \theta}{\cos \theta}

From the given statement:

\cos \theta = -\frac{4}{5} and sin < 0

⇒\theta lies in the 3rd quadrant.

then;

\sec \theta = \frac{1}{-\frac{4}{5}} = -\frac{5}{4}

Using trigonometry identities:

\sin \theta = \pm \sqrt{1-\cos^2 \theta}

Substitute the given values we have;

\sin \theta = \pm\sqrt{1-(\frac{-4}{5})^2 } =\pm\sqrt{1-\frac{16}{25}} =\pm\sqrt{\frac{25-16}{25}} =\pm \sqrt{\frac{9}{25} } = \pm\frac{3}{5}

Since, sin < 0

⇒\sin \theta = -\frac{3}{5}

now, find \tan \theta:

\tan \theta = \frac{\sin \theta}{\cos \theta}

Substitute the given values we have;

\tan \theta = \frac{-\frac{3}{5} }{-\frac{4}{5} } = \frac{3}{5}\times \frac{5}{4} = \frac{3}{4}

Therefore, the exact value of:

(a)

\sec \theta =-\frac{5}{4}

(b)

\tan \theta= \frac{3}{4}

7 0
4 years ago
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