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2 years ago

HELP ME PLEASE ASAP!!!!!!!!

Mathematics

1 answer:

sergij07 [2.7K]2 years ago

8 0

Answer:

(2, 14), (3, 7)

Step-by-step explanation:

The way these angles are numbered, corresponding angle numbers differ by 4, 8, or 12.

Corresponding angles are ...

Angle 2 and Angle 14 . . . . . . numbers differ by 12

Angle 3 and Angle 7 . . . . . . . numbers differ by 4

_____

If a given angle is Northwest of the intersection, any corresponding angle will also be Northwest of its intersection. Corresponding angles are ...

northwest: {1, 5, 9, 13}

northeast: {2, 6, 10, 14}

southeast: {3, 7, 11, 15}

southwest: {4, 8, 12, 16}

Any pair of numbers from the same set will be corresponding angles.

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2 years ago

What is the simplified form of 2/x^2-x - 1/x?

Pachacha [2.7K]

Answer: $\bold{(C)\ \dfrac{3 - x}{x(x-1)}}$

Step-by-step explanation:

$\dfrac{2}{x^2-x}-\dfrac{1}{x}$

$=\dfrac{2}{x(x-1)}+\dfrac{-1}{x}$

$=\dfrac{2}{x(x-1)}+\dfrac{-1}{x}\bigg(\dfrac{x-1}{x-1}\bigg)$

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8 0

3 years ago

Jillian measured the distance around a small fish pond as 27 yards. Which would be a good estimate for the distance across the p

DochEvi [55]

Assuming the fish pond is round, what you're given is the circumference.
So you know that 2πr = 27.
We want to solve for the diameter, or d = 2r. We should isolate that.
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3 0

2 years ago

Given that f(x) = 19x2 + 152, solve the equation f(x) = 0

telo118 [61]

Option A

The solution is:

$x = \pm 2i \sqrt{2}$

Solution:

$f(x) = 19x^2+152$

We have to solve the equation f(x) = 0

Let f(x) = 0

$0=19x^2+152$

Solve the above equation

$19x^2 + 152 = 0$

$\mathrm{Subtract\:}152\mathrm{\:from\:both\:sides}\\\\19x^2+152-152=0-152\\\\Simplify\ the\ above\ equation\\\\19x^2 = -152\\\\\mathrm{Divide\:both\:sides\:by\:}19\\\\\frac{19x^2}{19} = \frac{-152}{19}\\\\x^2 = -8$

Take square root on both sides

$x = \pm \sqrt{-8}\\\\x = \pm \sqrt{-1}\sqrt{8}\\\\\mathrm{Apply\:imaginary\:number\:rule}:\quad \sqrt{-1}=i\\\\x = \pm i\sqrt{8}\\\\x = \pm i \sqrt{2 \times 2 \times 2}\\\\x = \pm 2i\sqrt{2}$

Thus the solution is found

5 0

2 years ago