Let Marc's age be x. If Jeanine is twice as old as Marc, then her age will be 2x. If their ages added together are 24, then you can create the following equation:
2x + x = 24
3x = 24
x = 8
Remember that x is Marc's age. So if Marc is 8, and Jeanine is twice as old, she will be 16.
Answer:
ill give a guess because I cant read it
Ok so you have a equation already solved for a single variable which in this case is y. So just take 6x+2 and sub it in for all the y's in 3y-18x=12 3(6x+2)-18x=12. Now distribute the 3 to get 18x+6-18x=12. Next combine like terms to get 6=12 Now because we cant do anything else and our variable is canceled out and the equality of 6=12 is false the solution to this SoE would be No Solution. <span />
B is correct since there is one output for every input !!
have a great day :))
