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3 years ago

7

If the number of roaches triples every day, and there are 10 to start with, write an equation to represent this situation. How m

any roaches will there be after 15 days?

1 answer:

victus00 [196]3 years ago

8 0

Answer:

430,467,210

Step-by-step explanation:

ur answer maybe idk

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What fraction is greater than 0.7 but less than 0.71

alexgriva [62]

Are there any answer choices because this question has multiple answers.

4 0

3 years ago

Need answer ASAP giving points

dalvyx [7]

Answer:

$- \frac{11}{12}$

Step-by-step explanation:

$\frac{ \frac{5}{8} + \frac{3}{4} }{ \frac{ - 2}{3} - \frac{5}{6} } = \frac{ \frac{5}{8} + \frac{6}{8} }{ \frac{ - 4}{6} - \frac{5}{6} } \\ \\ = \frac{ \frac{5 + 6}{8} }{ \frac{ - 4 - 5}{6} } \\ \\ = \frac{ \frac{11}{8} }{ - \frac{9}{6} } \\ \\ = \frac{11}{8} \div ( - \frac{9}{6} ) \\ \\ = \frac{11}{8} \times ( - \frac{6}{9} ) \\ \\ = \frac{11}{8} \times ( - \frac{2}{3} ) \\ \\ = \frac{11}{4} \times ( - \frac{1}{3} ) \\ \\ = - \frac{11}{12}$

8 0

2 years ago

a boat travels upstream on the allegheny river for 2 hours. the return trip only takes 1.7 hours because the boat travels 2.5 mi

Gre4nikov [31]

To solve this we are going to use the speed equation: $S= \frac{d}{t}$
where
$S$ is speed
$d$ is distance
$t$ time

We know from our problem that the upstream trip takes 2 hours, so $t_{u}=2$ . We also know that the downstream trip takes 1.7 hours, so $t_{d}=1.7$ . Notice that the distance of both trips is the same, so we are going to use $d$ to represent that distance.
Now, lets use our equation to relate the quantities:

For the upstream trip:
$S_{u}= \frac{d}{t_{u} }$
$S_{u}= \frac{d}{2}$ equation (1)

For the downstream trip:
$S_{d}= \frac{d}{t_{d} }$
$S_{d}= \frac{d}{1.7}$ equation (2)

We know that the boat travels 2.5 miles per hour faster downstream, so the speed of the boat upstream will be the speed of the boat downstream minus 2.5 miles per hour:
$S_{u}=S_{d}-2.5$ equation (3)

Replacing (3) in (1):
$S_{u}= \frac{d}{2}$
$S_{d}-2.5= \frac{d}{2}$ equation (4)

Solving for $d$ in equation (2):
$S_{d}= \frac{d}{1.7}$
$d=1.7S_{d}$ equation (5)

Replacing (5) in (4):
$S_{d}-2.5= \frac{d}{2}$
$S_{d}-2.5= \frac{1.7S_{d}}{2}$
$2(S_{d}-2.5)=1.7S_{d}$
$2S_{d}-5=1.7S_{d}$
$0.3S_{d}=5$
$S__{d}= \frac{5}{0.3}$
$S_{d}= \frac{50}{3}$ equation (6)

Replacing (6) in (5)
$d=1.7S_{d}$
$d=1.7( \frac{50}{3} )$
$d= \frac{85}{3}$ miles

We can conclude that the boat travel $\frac{85}{3}$ , which is approximately 28.3 miles, in one way.

5 0

3 years ago

Pls help me. Look at the photo:)

Phoenix [80]

Answer:

i am goin to say C

Step-by-step explanation:

8 0

2 years ago

Y=-1 and 1/4x+5<br>y=x+2<br>answer choice<br>a.(-5,-3)<br>b.(12/5,22/5)<br>c.(1,3)<br>SHOW WORK !!

-BARSIC- [3]

Answer is B. Work attached. :)

5 0

2 years ago