Answer:
1. 10s
2. Slower than normal
Explanation:
1. To calculate the normal time, we first take the average of Charlene's observed times:
Average of Charlene's observed time =
= 8.5s
Her normal time is therefore:
=
= 10s
2. Since no of Charlene's observed time is higher than normal time of 10s, we can therefore conclude that her work perfomance should be rated as slower than normal.
The statement in situations where an annual budget deficit exists, cutting expenses from the budget is optimal is True.
<h3>What is budget deficit?</h3>
Budget deficit tend to occur when the expenses or expenditure is higher then the revenue.
Cutting down expenses from the budget is most desirable if we want to have budget surplus. Budget surplus is when revenue is higher than expenditure.
Therefore the statement in situations where an annual budget deficit exists, cutting expenses from the budget is optimal is True.
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Answer:
A. $57,000
B. Depreciation rate per mile is $0.19
C. Depreciation is $14,630
Explanation:
a. cost of the truck less the residual value.
Cost of the truck $69,000
Less: Residual value <u>$12,000</u>
$57,000
b. Depreciation rate per mile is computed by dividing cost of the truck less the residual value over the estimated useful life.
$57,000 / 300,000 miles = $0.19
c. Units-of-activity depreciation for the year is computed by multiplying miles driven for the year by depreciation rate per mile.
77,000 miles x $0.19 = $14,630
Answer:
236.23
Explanation:
The computation of X is shown below:-
As per the time-weighted method
The 6-month yield
= (40 ÷ 50) × (80 ÷ 60) × (157.50 ÷ 160) - 1
= 5%
Annual equivalent = (1.05)^2 - 1
= 10.25%
1 - year yield = (40 ÷ 50) × (80 ÷ 60) × (175 ÷ 160) × (X ÷ 250) - 1
= 0.1025
X(0.004667) = 1.1025
X = 236.23
Therefore on December 31st the value of account of X = 236.25
Answer:
a) X1=5.64
X2=4.57
X3= 8.59
Optimal solution=104.77
b) Additional hour on machine 3 = 105.42 – 104.77 = 0.64
c) Additional 15 hours on machine 2 = 105.37-104.77 = 0.6
Explanation:
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