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andreyandreev [35.5K]
3 years ago
10

Center at (3, 4); passes through (3, 10) and (3, -2); b = 2

Mathematics
1 answer:
Amanda [17]3 years ago
7 0

Answer:

  m,nmm,,m

Step-by-step explanation:

hvhhvh

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Which polynomial function has a leading coefficient of 1 and roots 21 and 31 with multiplicity 1?
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Answer:

Which i think is the first one, there may just be a typing error.

Step-by-step explanation:

A polynomial of order n has the following format:

f(x) = a(x - x_{0})(x - x_{1})...(x - x_{n-1})

In which a is the leading coefficient, x_{0}, x_{1},..., x_{n-1} are the roots.

If a root appears m times, they are said to have multiplicity m.

Leading coefficient of 1 and roots 21 and 31 with multiplicity 1

f(x) = 1(x - 21)(x - 31)

So the correct answer is:

f(x) = 1(x - 21)(x - 31)

Which i think is the first one, there may just be a typing error.

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