Hello,
3x²-26x+16=3x²-24x-2x+16=3x(x-8)-2(x-8)=(x-8)(3x-2)
Perimeter= 2*(x-8+3x-2)=2*(4x-10)=8x-20
( 1, ∞) is the domain of (b o a)(x)
<h3>
What is Function?</h3>
A function is defined as a relation between a set of inputs having one output each.
According to the question,

To find the domain of the composite function,

Therefore,

Hence , [ 1, ∞ ] is is the domain of (b o a)(x).
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D, you have to factor 3 out of 6x squared
Start by looking at the vertex form of a quadratic function, f(x) = a(x - h)^2 + k. The variables h and k are the values of the vertex. Plug those in to get f(x) = a(x - 4)^2 + 5. To find the variable a, plug in the point given for the x and y values. So, you get (21) = a((8) - 4)^2 + 5. Solve for a algebraically, and you get a = 1. Finally, plug everything in and simplify the equation. You should get that the quadratic function is f(x) = x^2 - 8x + 21. Hope this helps!
The value of cos(L) in the triangle is Five-thirteenths
<h3>What are right triangles?</h3>
Right triangles are triangles whose one of its angle has a measure of 90 degrees
<h3>How to determine the value of cos(L)?</h3>
The value of a cosine function is calculated as:
cos(L) = Adjacent/Hypotenuse
The hypotenuse is calculated as
Hypotenuse^2 = Opposite^2 + Adjacent^2
So, we have:
Hypotenuse^2 = 12^2 + 5^2
Evaluate
Hypotenuse^2 = 169
Take the square root of both sides
Hypotenuse = 13
So, we have
Adjacent = 5
Hypotenuse = 13
Recall that
cos(L) = Adjacent/Hypotenuse
This gives
cos(L) = 5/13
Hence, the value of cos(L) in the triangle is Five-thirteenths
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