If you reflect (–2, –8) across both axes, which quadrant will it be in?
2 answers:
Right now, the coordinate is in quadrant III.
It doesn't matter which one (axis) you reflect off of first.
If you do x first, it would go to quadrant II, (over the x-axis) and then to I (over the y-axis)
If you do y first, then it would go to IV then to l.
So, (-2,-8) will land on the first Quadrant.
I hope this helps!
~kaikers
It doesn't matter which one (axis) you reflect off of first.
If you do x first, it would go to quadrant II, (over the x-axis) and then to I (over the y-axis)
If you do y first, then it would go to IV then to l.
So, (-2,-8) will land on the first Quadrant.
I hope this helps!
~kaikers
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Given:
Tangent segment MN = 6
External segment NQ = 4
Secant segment NP =x + 4
To find:
The length of line segment PQ.
Solution:
Property of tangent and secant segment:
If a secant and a tangent intersect outside a circle, then the product of the secant segment and external segment is equal to the product of the tangent segment.
Subtract 16 from both sides.
Divide by 4 on both sides.
The length of line segment PQ is 5 units.