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Gelneren [198K]
3 years ago
5

How do you use protractors, its been printed on the paper, this is gonna be a little confusing for me sorry if I give this app a

hard time.. Not lying

Mathematics
1 answer:
Luda [366]3 years ago
7 0

Answer:

  see below

Step-by-step explanation:

A protractor is usually a transparent measuring device laid intended to be laid over an angle to be measured. The centerpoint of the protractor's scale is made to coincide with the angle's vertex, and the baseline of the protractor is aligned with one of the angle's rays. The appropriate scale is used to read the angle where the other ray crosses the scale. You usually have to visually determine if the angle is acute or obtuse, so you can choose the correct scale to read.

__

If you're drawing an angle, first draw one ray and locate the vertex on it. Then do the steps above as you would for measurement. Make a mark on your paper corresponding to the desired angle measure, and connect the vertex to that mark to create the other ray of the angle.

__

If you're working with a printed protractor, you may need to do your work on a piece of translucent paper or transparency material, so you can see the protractor scale through the page you're drawing on.

_____

<em>Comment on a printed protractor</em>

A protractor will only give accurate measurements if its geometry is perfect. Some printers will scale a figure differently in horizontal and vertical directions, so will make the protractor scale be elliptical instead of circular. That will give wrong readings.

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“An architect is planning to incorporate several stone spheres of different sizes into the landscaping of a public park, and wor
Artist 52 [7]

Answer:

Part 1) The value that is closest to the cost of finishing a sphere with a 5.50-meter circumference is $900

Part 2) The value that is closest to the cost of finishing a sphere with a 7.85-meter circumference is $1,800

Step-by-step explanation:

Step 1

Find the radius of each sphere

we know that

The circumference of a circle is equal to

C=2\pi r

<u><em>Find the radius of the sphere with a 5.50-meter circumference</em></u>

For C=5.50\ m

assume

\pi =3.14

substitute and solve for r

5.50=2(3.14)r

r=5.50/[2(3.14)]=0.88\ m

<u><em>Find the radius of the sphere with a 7.85-meter circumference</em></u>

For C=7.85\ m

assume

\pi =3.14

substitute and solve for r

7.85=2(3.14)r

r=7.85/[2(3.14)]=1.25\ m

step 2

Find the surface area of each sphere

The surface area of sphere is equal to

SA=4\pi r^{2}

<u><em>Find the surface area of sphere with a 5.50-meter circumference</em></u>

For r=0.88\ m

assume

\pi =3.14

substitute

SA=4(3.14)(0.88)^{2}

SA=9.73\ m^{2}

<u><em>Find the surface area of sphere with a 7.85-meter circumference</em></u>

For r=1.25\ m

assume

\pi =3.14

substitute

SA=4(3.14)(1.25)^{2}

SA=19.63\ m^{2}

step 3

Find the cost of finishing each sphere

we know that

To find out the cost , multiply the surface area by $92 per square meter

<u><em>Find the cost of sphere with a 5.50-meter circumference</em></u>

9.73*(92)=\$895.16

therefore

The value that is closest to the cost of finishing a sphere with a 5.50-meter circumference is $900

<u><em>Find the cost of sphere with a 7.85-meter circumference</em></u>

19.63*(92)=\$1,805.96

therefore

The value that is closest to the cost of finishing a sphere with a 7.85-meter circumference is $1,800

6 0
3 years ago
Linda won $200,000 in a state lottery. She first paid income tax on 30% on the winnings. She invested some of the rest at 1.5% a
Lady_Fox [76]

She invested $ 50000 at 1.5% rate and $ 90000 at 4% rate.

<u><em>Explanation</em></u>

Total amount of winnings = $ 200000

She first paid income tax on 30% on the winnings. So, the amount paid as income tax =(200000*0.30)dollar=60000 dollar.

<u>Remaining amount</u> = $ 200000 - $ 60000 = $ 140000

Suppose, she invested  x dollar at 1.5% rate.

That means, she invested (140000-x) dollar at 4% rate.

Given that, the total amount of interest earned = $ 4350

So, the equation will be.....

0.015x+0.04(140000-x)=4350\\ \\ 0.015x+5600-0.04x=4350\\ \\ -0.025x= 4350-5600\\ \\ -0.025x=-1250\\ \\ x= \frac{-1250}{-0.025}=50000

So, amount of investment at 1.5% rate = $ 50000

and amount of investment at 4% rate = $ 140000 - $ 50000 = $ 90000  


5 0
3 years ago
The commuting time for a student to travel from home to a college campus is normally distributed with a mean of 30 minutes and a
Rainbow [258]

Answer:

0.1587

Step-by-step explanation:

Let X be the commuting time for the student. We know that X\sim N(30, (5)^2). Then, the normal probability density function for the random variable X is given by

f(x) = \frac{1}{\sqrt{2\pi(5)^{2}}}\exp[-\frac{(x-\mu)^{2}}{2(5)^{2}}]. We are seeking the probability P(X>35) because the student leaves home at 8:25 A.M., we want to know the probability that the student will arrive at the college campus later than 9 A.M. and between 8:25 A.M. and 9 A.M. there are 35 minutes of difference. So,

 

P(X>35) = \int\limits_{35}^{\infty}f(x)dx = 0.1587

To find this probability you can use either a table from a book or a programming language. We have used the R statistical programming language an the instruction pnorm(35, mean = 30, sd = 5, lower.tail = F)

6 0
3 years ago
Hey there .. Plz help me solve this . ​
Ivahew [28]

Answer:

I don't understand your question!!!

7 0
2 years ago
If the mean is 298 and standard deviation is 22 what is the probability that a random sample of 42 pregnancies has a mean gestat
anyanavicka [17]

Answer:

The probability is 0.9909.

Step-by-step explanation:

Test statistic (z) = (sample mean - population mean) ÷ (sd/√n)

sample mean = 290 days

population mean = 298 days

sd = 22 days

n = 42

z = (290 - 298) ÷ (22/√42) = -8 ÷ 3.395 = -2.36

The cumulative area of the test statistic is the probability that the mean gestation period is less than 290 days. The cumulative area is 0.9909. Therefore the probability is 0.9909.

7 0
3 years ago
Read 2 more answers
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