Let
x-------> the amount of
solution
y--------> the amount of
solution
we know that
so

-------> equation A
-------> equation B
substitute equation A in equation B




find the value of y


therefore
The student need
of
solution and
of
solution
<u>the answer is</u>
A) The percent values were written incorrectly in the equation
B) The amount of 7% solution should be written as 1 – x, not x – 1.
Answer:
H0 : μEng = μBio
H1: μEng ≠ μBio
Step-by-step explanation:
μEng = Engineering average gpa
μBio = Biology average gpa
To test for difference between two sample means , in this case grade point average of biology majors and Engineering major.
Null hypothesis is the initial truth, which is that ; there is no difference in the mean grade point average of both biology and engineering majors
H0 : μEng = μBio
The Alternative hypothesis is the opposite of the null, which is stated has ; there is difference between the average GPA of both Engineering and Biology majors
H1: μEng ≠ μBio
Answer:
3 1/3
Step-by-step explanation:
Isolate the variable by dividing each side by factors that don't contain the variable.
Exact Form:
x
=
10
/3
Decimal Form:
x
=
3.
3
3
Mixed Number Form:
x = 3 1/3
Answer:
4 number
Step-by-step explanation:
16p+32q=1,280
y= 2*x / x+3 that is my answer