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tensa zangetsu [6.8K]
3 years ago
8

Tomo, Inc. has prepared its third quarter budget and provided the following data:: Jul Aug SepCash collections $50,000 $39,600 $

46,100Cash payments: Purchases of direct materials 30,000 21,700 17,600Operating expenses 12,300 8,000 11,600Capital expenditures 13,700 24,300 0The cash balance on June 30 is projected to be $4500. The company has to maintain a minimum cash balance of $5,000 and is authorized to borrow at the end of each month to make up any shortfalls. It may borrow in increments of $5,000 whenever there is surplus cash. How much will the company have to borrow at the end of July?
Business
1 answer:
dexar [7]3 years ago
3 0

Answer:

The firm will needto borrow 6,500 to achieve their minimum cahs balance and pay  their budgeted expenditures

Explanation:

                       July

beginning          $     4,500

receipts                  $   50,000

disbursement+  $  (56,000)*

subtotal                  $     (1,500)

minimun                         $5,000

Financing needs: 5000 - (-1500)  = 6,500

payment/loan  $6,500

*sum of cash payment for purchase of materials, operating expenses and capital expenditures

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Company strategies evolve because

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4 years ago
Wang Co. manufactures and sells a single product that sells for $640 per unit; variable costs are $352 per unit. Annual fixed co
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Answer:

The correct answer is 45%.

Explanation:

According to the scenario, the given data are as follows:

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Variable cost = $352

Annual fixed cost = $985,500

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So, we can calculate the contribution margin ratio by using following formula:

Contribution margin ratio = (Contribution margin per unit ÷ selling price per unit ) × 100

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3 years ago
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7 0
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Slim made a single deposit of $5,000 in an account that pays 7.2% in 2015. What equal-sized annual withdrawals can Slim make fro
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Annual Interest Rate = 7.2%

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solution

we consider equal sized annual withdrawals = x

so we can say that Amount Deposited amount will be as

$5,000 = \frac{x}{(1+0.72)^5} + \frac{x}{(1+0.72)^6} + \frac{x}{(1+0.72)^7} + \frac{x}{(1+0.72)^8} + \frac{x}{(1+0.72)^9} + \frac{x}{(1+0.72)^{10}}       ..........1

we take common here \frac{x}{(1+0.72)^{4}}

so

$5,000 = \frac{x}{(1+0.72)^{4}} \times ( \frac{1}{(1+0.72)^1} + \frac{1}{(1+0.72)^2} + \frac{1}{(1+0.72)^3} + \frac{1}{(1+0.72)^4} + \frac{1}{(1+0.72)^5} + \frac{1}{(1+0.72)^{6}} )      

solve it we get

x = $1,393.87  

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