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olya-2409 [2.1K]
3 years ago
9

Angie and Eric have opened a jumbo bag of candies and counted the number of each color. They have 100 red, 180 green, 90 yellow,

and 130 brown candies. Sarah and Laney each take turns drawing a candy, replacing each candy after they draw. If Angie and Eric each draw a candy 500 times, how many times should they expect for Angie to draw a brown candy followed by Eric drawing a red candy?
Mathematics
1 answer:
7nadin3 [17]3 years ago
8 0

Answer:

26 times.

Step-by-step explanation:

Total number of candies = 500.

Probability ( Angie drawing a brown candy) = 130/500  = 13/50.

Probability (Eric drawing a red candy) = 100/500 = 1/5.

So Probability ( Angie drawing brown then Eric drawing a red) = 13/50 * 1/5

= 13/250.

Therefore the expectation  of the number of times this will happen

= Probability * total number of draws

=  (13/250) * 500

= 13 * 2

=  26 times.

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  see the attachment

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The simulation of 70 different choices of a random class is shown in the attachment.

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<em>Comment on the question</em>

IMO, the use of <em>70 trials</em> is coincidentally the same number as the first <em>70 days</em> of school. The calendar is deterministic, so there will be exactly 14 Fridays in that period. If, in 70 draws, you get 16 yellow marbles, you cannot say, "the probability of a Friday is 16/70." You need to be very careful to properly state the question you're trying to answer.

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