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3 years ago

13

Please help

2 answers:

Eva8 [605]3 years ago

8 0

146.65 becuase 12.3 plus 25.75 plus 108.6 equals 146.65

insens350 [35]3 years ago

4 0

The answer is 146.65 because if you add all of hen together you get the sum

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Find the area of the triangle enclosed by these lines with the following vertices. y = x, x = 0, y = 5 (0,0), (0,5), (5,5)

Lina20 [59]

The are of the triangle will be 12.5 units.

On marking the given vertices (0,0), (0,5), (5,5) of the triangle we get, the base of the triangle = 5 units and height of the triangle = 5 units.

Now, we know area of triangle = $\frac{Base * Height}{2} \\ \\ = \frac{5 *5}{2} \\ \\ = \frac{25}{2} \\ \\ = 12.5 units.$

4 0

3 years ago

Really need help asap!!

sp2606 [1]

The answer is 799 ur welcome

8 0

3 years ago

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When evaluating (3.25 times 10 Superscript 5 Baseline) (1.82 times 10 Superscript 3 Baseline), what will be the exponent of 10 i

boyakko [2]

Answer:

The exponent of 10 in the product is 8.

Step-by-step explanation:

The expression is as follows:

$(3.25\times 10^{5})\cdot (1.82\times 10^{3})$

Exponent rule:

$a^{m}\times a^{n}=a^{m+n}$

Simplify the expression as follows:

$(3.25\times 10^{5})\cdot (1.82\times 10^{3})=3.25\times 10^{5}\times 1.82\times 10^{3}$

$=(3.25\times 1.82)\times (10^{5}\times 10^{3})\\\\=5.915\times 10^{5+3}\\\\=5.915\times 10^{8}$

Thus, the exponent of 10 in the product is 8.

3 0

3 years ago

Read 2 more answers

As a person cycling increases speed, the rate of calorie burned, distance traveled, and energy expended also increase. Which of

ella [17]

Answer:

c because the distance is important

7 0

3 years ago

Tim has an after-school delivery service that he provides for several small retailers in town. He uses his bicycle and charges $

nlexa [21]

Answer:

<em>$4.84</em>

<em></em>

Step-by-step explanation:

Given that

For delivery within $1\frac{1}2$ mi, charges = $1.25

For delivery within $1\frac{1}2$ mi - $1\frac{3}4$ mi, charges = $1.70

For delivery within $1\frac{3}4$ mi - 2 mi, charges = $2.15

and

so on.

i.e.

For delivery within 2 mi - 2 $\frac{1}4$ mi, charges = $2.60

For delivery within 2 $\frac{1}4$ mi - 2 $\frac{1}2$ mi, charges = $3.05

For delivery within 2 $\frac{1}2$ mi - 2 $\frac{3}4$ mi, charges = $3.50

For delivery within 2 $\frac{3}4$ mi - 3 mi, charges = $3.95

For delivery within 3 mi - 3 $\frac{1}4$ mi, charges = $4.40

So, every 0.25 mi or $\frac{1}4$ mi increase in distance, there is an increase of $0.45 in the charges.

It is given that there is increase of 10% in the rates.

i.e. for every 0.25 mi increase in distance, there is an increase of 0.45*1.10 = $0.495 in the charges.

The distance of $3\frac{1}8$ miles lies within the range 3 mi - 3 $\frac{1}4$ mi.

So actual charges after increase of 10%

$\Rightarrow \$4.40 \times \dfrac{110}{100}\\\Rightarrow \$4.40 \times 1.10\\\Rightarrow \bold{\$4.84}$

6 0

4 years ago