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2 years ago

The house has a form of a rectangle with one side two and a half times as long as the other side.

Mathematics

1 answer:

Studentka2010 [4]2 years ago

4 0

Answer:

A. (x*2.5)*x

B. (32*2.5)*32=2560

Step-by-step explanation:

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Quadrilateral CAMP below is a rhombus. the length PQ is (x+2) units, and the length of QA is (3x-14) units. Which statements bes

valentinak56 [21]

Answer:

<h3>Q cuts the diagonal PA into 2 equal halves, since the diagonals of rhombus meet at right angles.</h3><h3>The value of x is 8.</h3>

Step-by-step explanation:

Given that Quadrilateral CAMP below is a rhombus. the length PQ is (x+2) units, and the length of QA is (3x-14) units

From the given Q is the middle point, which cut the diagonal PA into 2 equal halves.

By the definition of rhombus, diagonals meet at right angles.

Implies that PQ = QA

x+2 = 3x - 14

x-3x=-14-2

-2x=-16

2x = 16

dividing by 2 on both sides, we will get,

$x =\frac{16}{2}$

<h3>∴ x=8</h3><h3>Since Q cuts the diagonal PA into 2 equal halves, since the diagonals of rhombus meet at right angles we can equate x+2 = 3x-14 to find the value of x.</h3>

The line segment $\overrightarrow{PA}=\overrightarrow{PQ}+\overrightarrow{QA}$

$\overrightarrow{PA}=x+2+3x-14$

$=4x-12$

$=4(8)-12$ ( since x=8)

$=32-12$

$=20$

<h3>∴ $\overrightarrow{PA}=20$ units</h3>

3 0

2 years ago

A ramp with a constant incline is made to connect a driveway to a front door. At a point 4 feet from the driveway, the height of

harkovskaia [24]

Let A(4,12) and B(6,18)

RATE OF CHANGE = m = (y₂ - y₁) / (x₂ - x₁) = (18-12)/ (6-4)

m= 6/2 or m = 3

4 0

2 years ago

Read 2 more answers

Help please work with answer

Basile [38]

All you have to do is take the size for every cereal, divide it with its price and you should get your answer as cents. then compare them all and see which one has the lowest price.

* don't forgot to put place holders and add a decimal.

3 0

2 years ago

Help please I need answers for these questions

LekaFEV [45]

I think because the angles are corresponding/opposite to each other u equate them to 180°

7 0

2 years ago

Jerome burns 4 cal/min walking and 10 cal/min running. He walks between 10 and 20 min each day and runs between 30 and 45 min ea

erik [133]

Answer:

20 minutes should spend on walking and 30 minutes on running.

Step-by-step explanation:

Let x represents the minutes spent on walking and y represents the minutes spent on running,

∵ He burns 4 cal/min walking and 10 cal/min running,

So, the total calories burnt,

Z = 4x + 10y

Which has to be maximised.

Now, he walks between 10 and 20 min each day,

i.e. 10 < x < 20,

Also, he runs between 30 and 45 min each day,

i.e. 30 < y < 45,

By graphing 10 < x < 20 and 30 < y < 45,

We obtained the vertices of feasible region,

(10, 45), (20, 45), (10, 30) and (20, 30)

At (10, 45),

Z = 4(10) + 10(45) = 40 + 450 = 490,

At (20, 45),

Z = 4(20) + 10(45) = 80 + 450 = 530,

At (10, 30),

Z = 4(10) + 10(30) = 40 + 300 = 340,

At (20, 30)

Z = 4(20) + 10(30) = 80 + 300 = 380

Hence, maximum calories is 530 when 20 minutes spent on walking and 30 minutes spent on running.

5 0

2 years ago