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Ronch [10]
3 years ago
14

If a sample of the heat-killed bacteria is treated with a DNase would you expect transformation to occur? Explain.

Biology
1 answer:
Nutka1998 [239]3 years ago
8 0
No idea you need to look in google for the answer
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Describe the dna structure using the terms nucleotides, backbone, and orientation.
Alona [7]

The term DNA stands for deoxyribonucleic acid and contains genetic information in its double-stranded helical structure.

Explanation:

A nucleotide can be said to be the basic building block of the DNA molecule. Each of these nucleotides is composed of three components:

  1. A phosphate group
  2. A sugar group
  3. A nitrogen base

The genetic code contained within the DNA is determined by the sequence/order in which these bases occur.

The DNA backbone is made up of the sugar-phosphate nucleic acids framework. These groups occur in an alternating manner, in repeating patterns.

The structure of DNA is fairly regular, as in the following parameters are constant - orientation, length of the strand, width and number of nucleotides. These double-stranded molecules are asymmetrical, with the two disjoint strands intertwined with each other, connected by means of hydrogen bonds.

7 0
3 years ago
If someone in college has their major in nutrition and chemistry from what you eat, then they are studying...
lesya692 [45]

Answer:

Food Engineering

Explanation:

It is also known as food engineering, where the nutritional degree of food, its chemical components, its formation and production, its conservation and the industrial methods involved in marketing it are studied.

3 0
3 years ago
The period adolescence in which teenagers experince rapid physical growth and hormonal changes is
UNO [17]
Puberty probably idk
5 0
3 years ago
What is the probability that each of the following pairs of parents will produce the indicated offspring? (Assume independent as
ASHA 777 [7]

Answer:

(a) AABBCC × aabbcc->AaBbCc     → 1

(b) AABbCc × AaBbCc->AAbbCC   → 1/32

(c) AaBbCc × AaBbCc->AaBbCc     → 1/8

(d) aaBbCC × AABbcc->AaBbCc    → 1/2

Explanation:

In such cases we calculate the probability of each allelic pair separately.

(a) AABBCC × aabbcc -> AaBbCc  

Aa  Aa   Aa  Aa           Bb  Bb  Bb  Bb         Cc  Cc  Cc  Cc

↓                                   ↓                                ↓  

4/4 = 1                          4/4 = 1                       4/4 = 1    

In case of gene A, out of the 4 probable allelic combinations, 4 will be Aa so the probability is 4/4 = 1.

In case of gene B, out of the 4 probable allelic combinations, 4 will be Bb so the probability is 4/4 = 1.

In case of gene C, out of the 4 probable allelic combinations, 4 will be Cc so the probability is 4/4 = 1.

So, the total probability of getting AaBbCc   = 1 x 1 x 1 = 1.                

(b) AABbCc × AaBbCc -> AA bb CC

AA  AA   Aa  Aa           BB  Bb  Bb  bb         CC  Cc  Cc  cc

↓                                                        ↓           ↓  

2/4                                                    1/4          1/4

In case of gene A, out of the 4 probable allelic combinations, 2 will be AA so the probability is 2/4.

In case of gene B, out of the 4 probable allelic combinations, 1 will be bb so the probability is 1/4.

In case of gene C, out of the 4 probable allelic combinations, 1 will be CC so the probability is 1/4.

So, the total probability of getting AA bb CC = 2/4 x 1/4 x 1/4 = 1/32.

(c) AaBbCc × AaBbCc -> AaBbCc

AA  Aa   Aa  aa           BB  Bb  Bb  bb         CC  Cc  Cc  cc

        ↓                                  ↓                               ↓  

       2/4                               2/4                           2/4

In case of gene A, out of the 4 probable allelic combinations, 2 will be Aa so the probability is 2/4.

In case of gene B, out of the 4 probable allelic combinations, 2 will be Bb so the probability is 2/4.

In case of gene C, out of the 4 probable allelic combinations, 2 will be Cc so the probability is 2/4.

So, the total probability of getting AaBbCc = 2/4 x 2/4 x 2/4 = 1/8.

(d) aaBbCC × AABbcc->AaBbCc

Aa  Aa   Aa  Aa               BB  Bb  Bb  bb          Cc  Cc  Cc  Cc

      ↓                                        ↓                                ↓  

4/4 = 1                                       2/4                          4/4 = 1    

In case of gene A, out of the 4 probable allelic combinations, 4 will be Aa so the probability is 4/4 = 1.

In case of gene B, out of the 4 probable allelic combinations, 2 will be Bb so the probability is 2/4.

In case of gene C, out of the 4 probable allelic combinations, 4 will be Cc so the probability is 4/4 = 1.

So, the total probability of getting AaBbCc = 1 x 2/4 x 1 = 1/2.

5 0
3 years ago
1. Which of the following flowers can be white in color?
Darya [45]

Answer:

C: Tuberose

Explanation:

6 0
3 years ago
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