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3 years ago

7

The polynomial is a difference squares. Use the formula a^2 -b^2=(a+b)(a-b) to factor completely. 81x^2-49 the value of a is the

value of b is the product of the prime factors is

2 answers:

AnnZ [28]3 years ago

6 0

Answer: $(9x)^{2}-(7)^{2}=(9x-7)(9x+7)$

Step-by-step explanation:

1. By definition you have that the difference of squares is:

$a^{2}-b^{2}=(a+b)(a-b)$

2. Given the polynomial:

$81x^{2}-49$

You can identify that there are two terms whose signs are different and they are perfect squares.

3. Therefore, you have:

$81x^{2}-49=(9x)^{2}-(7)^{2}=(9x-7)(9x+7)$

oksano4ka [1.4K]3 years ago

5 0

Answer:

(9x+7)(9x-7)

Step-by-step explanation:

We have given an expression.

81x²-49

We have to use difference formula which is given in question.

a²-b² =(a+b)(a-b)

We have to write given expression in above formula.

81x²-49 = (9x)²-(7)²

Using given formula , we have

81x²-49 = (9x+7)(9x-7)

Hence, the factors of given expression are (9x-7) and (9x+7).

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