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sweet-ann [11.9K]
3 years ago
6

Shryia read a 480-page-long book cover to cover in a single session, at a constant rate. After reading for 1.5 hours, she had 40

2 pages left to read.
Let P represent the number of pages left to read after t hours.

Complete the equation for the relationship between the number of pages left and number of hours.

Mathematics
2 answers:
svet-max [94.6K]3 years ago
8 0

Answer:

The required equation is P(t) = -52t + 480

Step-by-step explanation:

Consider the provided information.

Let P represent the number of pages left to read after t hours.

Shryia read a 480-page-long book cover to cover in a single session, at a constant rate. After reading for 1.5 hours, she had 402 pages left to read.

Total number of page Shryia read in 1.5 hours is:

480-402 = 78

It is given that the rate is constant i.e 1.5 hours,

Therefore, she read 78 pages in 1.5 hours.

She can read \frac{78}{1.5} = 52 page per hour

The required equation is:

P(t) = -52t + 480

Where t represents the number of hours.

exis [7]3 years ago
3 0

Answer:

Step-by-step explanation:

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2. Santiago wants the lateral surfaces of the
MakcuM [25]

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262 square feet  of the ramp will be painted red.

Step-by-step explanation:

The lateral surface is surface area of the sides of the ramp without including the top and bottom faces

The ramp shown has three surfaces

The 2 sides are triangles with length 20 and height 8.5

The back is a rectangle shape with length 12 and height 8.5

Step 1: Finding the  Area of triangle

The area of the triangle  = \frac{1}{2} length \times height

The area of the triangle  = \frac{1}{2} (20 \times 8.5)

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Area of rectangle = length  \times height

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8 0
3 years ago
A facilities manager at a university reads in a research report that the mean amount of time spent in the shower by an adult is
arlik [135]

Answer:

(a) <em>H₀</em>: <em>μ</em> = 5 vs. <em>Hₐ</em>: <em>μ</em> ≠ 5.

(b) The test statistic value is -3.67.

(c) The <em>p</em>-value of the test is 0.0025.

(d) The mean amount of time spent in the shower by an adult is different from 5 minutes.

Step-by-step explanation:

In this case we need to test whether the mean amount of time that college students spend in the shower is significantly different from 5 minutes.

The information provided is:

n=15\\\bar x=4.29\\s=0.75\\\alpha =0.01

(a)

The hypothesis for the test can be defined as follows:

<em>H₀</em>: The mean amount of time spent in the shower by an adult is 5 minutes, i.e. <em>μ</em> = 5.

<em>Hₐ</em>: The mean amount of time spent in the shower by an adult is different from 5 minutes, i.e. <em>μ</em> ≠ 5.

(b)

As the population standard deviation is not known we will use a <em>t</em>-test for single mean.

Compute the test statistic value as follows:

t=\frac{\bar x-\mu}{s/\sqrt{n}}\\\\=\frac{4.29-5}{0.75/\sqrt{15}}\\\\=-3.67

Thus, the test statistic value is -3.67.

(c)

Compute the <em>p</em>-value of the test as follows:

p-value=2\times P(t_{\alpha/2, (n-1)}

*Use a <em>t</em>-table.

Thus, the <em>p</em>-value of the test is 0.0025.

(d)

Decision rule:

If the <em>p</em>-value of the test is less than the significance level then the null hypothesis will be rejected and vice-versa.

<em>p</em>-value = 0.0025 < <em>α</em> = 0.01

The null hypothesis will be rejected at 1% level of significance.

Thus, concluding that the mean amount of time spent in the shower by an adult is different from 5 minutes.

7 0
3 years ago
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