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Arada [10]
3 years ago
7

Carolyn selected a tile randomly from the set shown below. What is the probability that she selected a white tile or a tile with

an even number?
Mathematics
1 answer:
KIM [24]3 years ago
8 0

Answer:

I think its 9/20

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URGENT PLEASE HELP Find the slope
hichkok12 [17]

Answer:

2/3

Step-by-step explanation:

Look it up

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7 0
3 years ago
In a population of bats living in a certain region, 30 percent have a wingspan greater than 10 inches. In a random sample of 80
Kisachek [45]

Answer:

The correct option is (e).

Step-by-step explanation:

In this case we need to determine whether there is any difference between the proportion of bats with a wingspan greater than 10 inches living outside the region from that of the bats living in the region.

The hypothesis can be defined as follows:

<em>H₀</em>: There is no difference between the proportion of bats with a wingspan greater than 10 inches living outside the region and of the bats living in the region, i.e. <em>p</em> - <em>p₀</em> = 0.

<em>Hₐ</em>: There is a difference between the proportion of bats with a wingspan greater than 10 inches living outside the region and of the bats living in the region, i.e. <em>p</em> - <em>p₀</em> ≠ 0.

The information provided is:

<em>n</em> = 80

<em>X</em> = 20

<em>p₀</em> = 0.30

A <em>z</em>-test for single proportion will be used to perform the analysis.

Compute the sample proportion of  bats living outside of the region having  a wingspan greater than 10 inches as follows:

p=\frac{X}{n}=\frac{20}{80}=0.25

The test statistic is given as follows:

z=\frac{p-p_{0}}{\sqrt{\frac{p_{0}(1-p_{0})}{n}}}

Compute the value of the test statistic as follows:

z=\frac{p-p_{0}}{\sqrt{\frac{p_{0}(1-p_{0})}{n}}}

  =\frac{0.25-0.30}{\sqrt{\frac{0.30(1-0.30)}{80}}}

  =\frac{0.25-0.30}{\sqrt{\frac{0.30\times 0.70}{80}}}

Thus, the test statistic is z=\frac{0.25-0.30}{\sqrt{\frac{0.30\times 0.70}{80}}}.

The correct option is (e).

5 0
4 years ago
Read 2 more answers
In a computer catalog, a computer monitor is listed as being 19 inches.This distance is the diagonal distance across the screen.
KATRIN_1 [288]
Let's use the Pythagorean Theorem to solve this.

One side is 10 inches, the other side we don't know, and the hypotenuse is 19 inches. We will call the side we don't know <em>x</em>.

Thus, 10^2 + x^2 = 19^2
x = \sqrt{19^2 - 10^2} = \sqrt{261} = \boxed{3\sqrt{29}}
5 0
4 years ago
-x+3y=10 <br><br> find x and y intercept
zloy xaker [14]
-x+3y=10 \\ \\&#10;\hbox{x-intercept: }  y=0: \\&#10;-x+3 \times 0=10 \\&#10;-x=10 \\&#10;\boxed{x=-10} \\ \\&#10;\hbox{y-intercept: } x=0: \\&#10;-0+3y=10 \\&#10;3y=10 \\&#10;y=\frac{10}{3} \\&#10;\boxed{y=3 \frac{1}{3}}
8 0
3 years ago
The median of Rae's data is 2.22 minutes, and the median of Doris' data is 2.14 minutes. The interquartile range for Rae is , an
JulsSmile [24]

Complete question :

Rae and Doris are training to swim a 200-meter freestyle race. The table lists their practice times during training camp.

Rae’s Times(minutes)-2.12, 2.01, 2.46, 2, 2.22, 2.31, 2.23

doris times(minutes)-2.32, 2.19, 2.26, 2.03, 2.11, 2.14, 2.07

The median of Raes data is(drop down box answers, 2,2.03,2.14,2.22)minutes,and the median of doris data is(drop down box answers, 2,2.03,2.14,2.22)minutes. The interquartile range for rae is(drop down box answers, 0.01,0.13,0.26,0.30), and the interquartile range for doris is(drop down box answers, 0.02,0.06,0.18,0.19). The two data sets overlap(drop down box answers,very little, a lot

Answer:

Rae's median = 2.22

Rae's IQR = 0.30

DORIS median = 2.14

Doris IQR = 0.19

Step-by-step explanation:

Given :

Rae's time :

Ordered data : 2, 2.01, 2.12, 2.22, 2.23, 2.31, 2.46

Median = 1/2(n+1)th term ; n = 7

Median = 1/2(8) = 4th term

Median = 2.22

Q1 = 1/4(8)th term

Q1 = 2nd term = 2.01

Q3 = 3/4(n + 1)th term

Q3 = 3/4(8)th term

Q3 = 6th term = 2.31

Interquartile range = Q3 - Q1 = 2.31 - 2.01 = 0.30

DORIS Data:

Ordered data: 2.03, 2.07, 2.11, 2.14, 2.19, 2.26, 2.32

Median = 1/2(n+1)th term ; n = 7

Median = 1/2(8) = 4th term

Median = 2.14

Q1 = 1/4(8)th term

Q1 = 2nd term = 2.07

Q3 = 3/4(n + 1)th term

Q3 = 3/4(8)th term

Q3 = 6th term = 2.26

Interquartile range = Q3 - Q1 = 2.26 - 2.07 = 0.19

6 0
3 years ago
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