Which point could be removed in order to make the relation a function? (–9, –8), (–{(8, 4), (0, –2), (4, 8), (0, 8), (1, 2)}
stepan [7]
We are given order pairs (–9, –8), (–{(8, 4), (0, –2), (4, 8), (0, 8), (1, 2)}.
We need to remove in order to make the relation a function.
<em>Note: A relation is a function only if there is no any duplicate value of x coordinate for different values of y's of the given relation.</em>
In the given order pairs, we can see that (0, –2) and (0, 8) order pairs has same x-coordinate 0.
<h3>So, we need to remove any one (0, –2) or (0, 8) to make the relation a function.</h3>
6500 pounds are necessary to cover 75000 square feet
Bear in mind that, when it comes to trigonometric functions, the location of the exponent can be a bit misleading, however recall that sin²(θ) is really [ sin( θ )]²,
![\bf 2sin^2(2x)=2\implies sin^2(2x)=\cfrac{2}{2} \\\\\\ sin^2(2x)=1\implies [sin(2x)]^2=1\implies sin(2x)=\pm\sqrt{1} \\\\\\ sin(2x)=\pm 1\implies sin^{-1}[sin(2x)]=sin^{-1}(\pm 1)](https://tex.z-dn.net/?f=%5Cbf%202sin%5E2%282x%29%3D2%5Cimplies%20sin%5E2%282x%29%3D%5Ccfrac%7B2%7D%7B2%7D%0A%5C%5C%5C%5C%5C%5C%0Asin%5E2%282x%29%3D1%5Cimplies%20%5Bsin%282x%29%5D%5E2%3D1%5Cimplies%20sin%282x%29%3D%5Cpm%5Csqrt%7B1%7D%0A%5C%5C%5C%5C%5C%5C%0Asin%282x%29%3D%5Cpm%201%5Cimplies%20sin%5E%7B-1%7D%5Bsin%282x%29%5D%3Dsin%5E%7B-1%7D%28%5Cpm%201%29)
Answer: The answer is 60
Step-by-step explanation: 40% = .4 because % means hundredths. So 40% = 40/100 = .4
Let x be the total number of marbles.
Then, .4x = 24
Divide both sides by .4
x = 60 and 24 is 40% of 60 marbles
Hey!
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Question Explanation:
In other words you can write 200,00 using a whole number and a power 10 using scientific notation!
In scientific notation you want a number less than 10 multiplied by 10 to the power of a number.
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Solution:
200,000 / 10 = 20,000
20,000 / 10 = 2,000
2,000 / 10 = 200
200 / 10 = 20
20 / 10 = 2
I divided 200,000 by 10 five times to get a number less than 10.
So, 5 is going to be the exponent.
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Answer:
2 x 10^5
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Hope This Helped! Good Luck!
