Answer:
A Mudslinger tire weighs 20.71 pounds and a Roadripper tire weighs 19.52 pounds
Step-by-step explanation:
Let the weight of a Mudslinger tire=m
Let the weight of a Roadripper tire=r
4 Mudslinger tires and 6 Roadripper tires weigh 200 pounds
4m+6r=200.....(i)
7 Mudslinger tires and 2 Roadripper tires weigh 184 pounds
7m+2r=184....(ii)
To find the values of m and r, we solve the two derived equations simultaneously.
4m+6r=200.....(i)
7m+2r=184....(ii)
Multiply (ii) by 3 to get (iii)
21m+6r=552....(iii)
4m+6r=200.....(i)
SUbtract (i) from (iii)
17m=352
m=352/17=20.71 pounds
Substitute m=20.71 in (i)
4(20.71)+6r=200
6r=200-82.84=117.16
r=117.16/6=19.52 pounds
Answer: DescriptionIn mathematical physics, the Yang–Mills existence and mass gap problem is an unsolved problem and one of the seven Millennium Prize Problems defined by the Clay Mathematics Institute, which has offered a prize of US$1,000,000 for its solution. The problem is phrased as follows: Yang–Mills Existence and Mass Gap.
Answer:
v = 8
Step-by-step explanation:
Expand
4v - 14 = 18
Rearrange
4v = 18 + 14
4v = 32
v = 8
k/9-1=12
We move all terms to the left:
k/9-1-(12)=0
We add all the numbers together, and all the variables
k/9-13=0
We multiply all the terms by the denominator
k-13*9=0
We add all the numbers together, and all the variables
k-117=0
We move all terms containing k to the left, all other terms to the right
k=117
Answer:
4.85
Step-by-step explanation:
All u have to do is add 3.75 and 1.1 if u do that the sum will be 4.85