3 years ago

Which of the following have both 2 and -5 as solutions.

2 answers:

5 0

$x_1=2\ \ \ and\ \ \ x_2=-5\\\\ \Rightarrow\ \ \ (x-x_1)(x-x_2)=(x-2)(x+5)=x^2+5x-2x-10=\\\\.\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ =x^2+3x-10\ \ \ \Rightarrow\ \ \ Ans.\ a.$

Stella [2.4K]3 years ago

3 0

$x_1=2;\ x_2=-5\\\\(x-2)(x-(-5))=(x-2)(x+5)=x^2+5x-2x-10=x^2+3x-10\\\\Answer:a.$

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