Methyl methacrylate was polymerized at a mass concentration of 200 g/dm3 in toluene using azobisisobutyronitrile (AIBN) as initi
ator at a mass concentration of 1.64 x 10-2 g/dm3 and a reaction temperature of 60°C. Calculate the initial rate of polymerization and the number average molar mass of poly(methyl methacrylate) formed in the initial stages of the reaction given that the relevant rate coefficients at 60°C are:
Initiator dissociation, kd = 8.5 x 10-6 s-1
Propagation, kp = 833 dm3 mol-1 s-1
Termination, kt = 9.3 x 106 dm3 mol-1 s-1
Transfer to monomer, ktrM = 3.93 x 10-3 dm3 mol-1 s-1
Transfer to solvent, ktrS = 7.34 x 10-3 dm3 mol-1 s-1
Initiator efficiency, f = 0.7 Termination by combination is negligible Density of initial solution of methyl methacrylate in toluene is 860 g/dm3
Initiator dissociation, kd = 8.5 x 10-6 s-1
Propagation, kp = 833 dm3 mol-1 s-1
Termination, kt = 9.3 x 106 dm3 mol-1 s-1
Transfer to monomer, ktrM = 3.93 x 10-3 dm3 mol-1 s-1
Transfer to solvent, ktrS = 7.34 x 10-3 dm3 mol-1 s-1
Initiator efficiency, f = 0.7 Termination by combination is negligible Density of initial solution of methyl methacrylate in toluene is 860 g/dm3
1 answer:
You might be interested in
cos θ = , sin θ =
, cot θ = 4/7, sec θ =
, cosec θ =
Trigonometric Ratios are values of all the trigonometric functions based on the value of the ratio of sides in a right-angled triangle.
Sin θ: Opposite Side to θ/Hypotenuse
Tan θ: Opposite Side/Adjacent Side & Sin θ/Cos
Cos θ: Adjacent Side to θ/Hypotenuse
Sec θ: Hypotenuse/Adjacent Side & 1/cos θ
Analysis:
tan θ = opposite/adjacent = 7/4
opposite = 7, adjacent = 4.
we now look for the hypotenuse of the right angled triangle
hypotenuse = =
=
sin θ = opposite/ hyp =
Rationalize, x
=
But θ is in the third quadrant(180 - 270) and in the third quadrant only tan and cot are positive others are negative.
Therefore, sin θ = -
cos θ = adj/hyp =
By rationalizing and knowing that cos θ is negative, cos θ = -
cot θ = 1/tan θ = 1/7/4 = 4/7
sec θ = 1/cos θ = 1/ = -
cosec θ = 1/sin θ = 1/ =
Learn more about trigonometric ratios: brainly.com/question/24349828
#SPJ1