Question

Can someone help me with these please?

Answer 1

Point-slope form: y-y1 = m(x-x1)

Standard form: ax + by = c

Slope-intercept form: y = mx+b

Start by finding the slope. We know it is negative since the line is decreasing. The slope is -4/3.

To create point-slope form, we need to get one point from the graph. Let's use (3,0).

$y = -\frac{4}{3}(x-3)$

To create slope-intercept form, we need the slope and the y-intercept. The y-intercept is the point where our equation crosses the y-axis. For this equation, it is 4.

$y = -\frac{4}{3}x + 4$

To get standard form, solve the equation in terms of C.

Point-slope form: y = -4/3(x-3)

Slope-intercept form: y = -4/3x + 4

Standard form: 4/3x + y = 4