Can someone help me with these please?

Mathematics

1 answer:

saul85 [17]2 years ago

7 0

Point-slope form: y-y1 = m(x-x1)

Standard form: ax + by = c

Slope-intercept form: y = mx+b

Start by finding the slope. We know it is negative since the line is decreasing. The slope is -4/3.

To create point-slope form, we need to get one point from the graph. Let's use (3,0).

$y = -\frac{4}{3}(x-3)$

To create slope-intercept form, we need the slope and the y-intercept. The y-intercept is the point where our equation crosses the y-axis. For this equation, it is 4.

$y = -\frac{4}{3}x + 4$

To get standard form, solve the equation in terms of C.

Point-slope form: y = -4/3(x-3)

Slope-intercept form: y = -4/3x + 4

Standard form: 4/3x + y = 4

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Could you please answer this precisely. Thank you!

OleMash [197]

The mathematical functions (equations) are matched to their graph line respectively as follows:

y = 960 - 78x: purple straight line.
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<h3>What is a linear function?</h3>

A linear function can be defined as a type of function whose equation is graphically represented by a straight line on the cartesian coordinate. Mathematically, a linear function is given by this equation:

y = mx ± c.

<h3>What is an exponential function?</h3>

An exponential function can be defined as a type of mathematical function whose values are generated by a constant that is raised to the power of the argument. Mathematically, an exponential function is represented by this formula:

f(x) = keˣ

Next, we would match each of the mathematical functions (equations) to their graph line respectively as follows: