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lana [24]
3 years ago
14

How is adding and subtracting decimals similar to adding and subtracting whole numbers

Mathematics
2 answers:
rjkz [21]3 years ago
7 0

It is similar because with adding and subtracting with whole numbers because you could literally just add a decimal to the whole number. For instance if I'm adding 2 plus 3 it could also be expressed as 2.0 plus 3.0 which would have given you the same answer but just with a .0 at the end of it.

bazaltina [42]3 years ago
3 0
Don't forget, for a whole number like the first term, the decimal point lies just to the right of the ones column. ... To subtract these numbers, first arrange the terms vertically, aligning the decimal points in each term. You can add zeroes to the right of the decimal point, to make it easier to align the columns
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Which score has a higher relative position, a score of 271.2 on a test for which = 240 and , or a score of 63.6 on a test for wh
Fittoniya [83]

Answer:

The score of 271.2 on a test for which xbar = 240 and s = 24 has a higher relative position than a score of 63.6 on a test for which xbar = 60 and s = 6.

Step-by-step explanation:

Standardized score, z = (x - xbar)/s

xbar = mean, s = standard deviation.

For the first test, x = 271.2, xbar = 240, s = 24

z = (271.2 - 240)/24 = 1.3

For the second test, x = 63.6, xbar = 60, s = 6

z = (63.6 - 60)/6 = 0.6

The standardized score for the first test is more than double of the second test, hence, the score from the first test has the higher relative position.

Hope this Helps!!!

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3 years ago
2x + 6 = 8 please help meee
grigory [225]

Answer:

x=1

Step-by-step explanation:

2x+6=8

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3 years ago
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Korolek [52]

Answer:

3

Step-by-step explanation:

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Write 5.84 as a mixed number in simplest form.
MAVERICK [17]

Answer:

5 84/100

Step-by-step explanation:

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5 84/100

5 21/25

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Step-by-step explanation:

(x^2-y^2)^2\\\\\text{use}\ (a-b)^2=a^2-2ab+b^2\\\\=(x^2)^2-2(x^2)(y^2)+(y^2)^2\\\\\text{use}\ (a^n)^m=a^{nm}\\\\=x^4-2x^2y^2+y^2\\-----------------------------

\text{Other solution}\\\\(x^2-y^2)^2\\\\\text{use}\ a^2-b^2=(a-b)(a+b)\\\\= [(x-y)(x+y)]^2\\\\\text{use}\ (ab)^n=a^nb^n\\\\=(x-y)^2(x+y)^2

7 0
3 years ago
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