Question

LEFT

Answer 1

Answer:

b. 2 and 3

Step-by-step explanation:

Solve for x

$x^{2} - 5x + 6 = 0$

Now factor

$(x - 2)(x - 3)$ It would be -2 and -3 because they add up to -5 and multiply to be 6 (a negative times a negative always equal a positive)

Don't forget that it's still equal to 0

$(x-2)=0$  $(x-3)=0$

Now solve for x in both equations

$x-2=0$                                        $x-3=0$

  $+2$   $+2$  add 2 to both sides         $+3$  $+3$  add 3 to both sides

     $x=2$                                              $x = 3$