Answer:
Unusual
Step-by-step explanation:
we know that
The z-score is a measure of how close the given data point is to the mean of the values given with the standard deviation
so
if its z-score is greater than or equal to -2, or less than or equal to 2., then the data value is considered ordinary
if its z-score is less than -2 or greater than 2, then the data value is considered unusual
Invested amount (P0 = £6000.
Rate of interest (r) = 3.4% = 0.034.
We know compound interest formula
A = P(1+r)^t
We need work out the value of his investment per year.
So, we need to plug t=1 and plugging values of P and r in the formula above, we get
A = 6000(1+0.034)^1
A = 6000(1.034)
A = 6204.
<h3>Therefore, the value of his investment per year is £ 6204.</h3>
Now, we need to work out the value of his investment after 3 years.
So, we need to plug t=3.
A = 6000(1+0.034)^3
A = 6000(1.034)^3
1.034^3=1.105507304
A = 6000 × 1.105507304
A = 6633.04
<h3>Therefore, the value of his investment after 3 year is £ 6633.04.</h3>
Usually, the more often it's compounded, the better. That's assuming that the percent is equal through all comparisons, however.
That is the formula to find the slope. Hope it will help you.
