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Andreas93 [3]
4 years ago
11

Can someone please help me URGEnt

Mathematics
2 answers:
VARVARA [1.3K]4 years ago
6 0

Answer:

A. y = ¼x  

Step-by-step explanation:

A direct proportion has the form

y = kx or k=y/x

1. Calculate k

k = 3/12 = ¼

2. Write the equation

y = ¼x

Elina [12.6K]4 years ago
4 0

Answer:

A. y=\frac{1}{4}x

Step-by-step explanation:

The Direct Proportionality equation is: f (x) = k.x, where k is the proportionality constant and f (x) is y.

So y = k.x is the mathematical formula or model.

The graphical representation of the direct proportionality function is a line that passes through the origin of coordinates.

In the given case, we must calculate the value of k and then replace it in the formula, being

y = 3

x = 12

k =?

If y = k.x, isolating k is obtained

k=\frac{y}{x}

k=\frac{3}{12}

Expressing the fraction in its simplest form, we have

k=\frac{3/3}{12/3}

k=\frac{1}{4}

Substituting that value in the original formula y = k.x, we have

y=\frac{1}{4}x

Hope this helps!

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Step-by-step explanation:

<u>GIVEN</u> :

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\begin{gathered}\end{gathered}

<u>TO</u><u> </u><u>FIND</u> :

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\begin{gathered}\end{gathered}

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\star{\underline{\boxed{\sf{\purple{Csa = 2 \pi rh}}}}}

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\begin{gathered}\end{gathered}

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\begin{gathered} \qquad{\longrightarrow{\sf{Csa = 2 \pi rh}}} \\  \\ \qquad{\longrightarrow{\sf{88 = 2 \times \dfrac{22}{7} \times r \times 14}}}  \\  \\ \qquad{\longrightarrow{\sf{88 =\dfrac{44}{7} \times r \times 14}}} \\  \\ \qquad{\longrightarrow{\sf{88 =\dfrac{44}{\cancel{7}}\times r \times  \cancel{ 14}}}}  \\  \\  \qquad{\longrightarrow{\sf{88 =44 \times r \times 2}}} \\  \\ \qquad{\longrightarrow{\sf{88 =88 \times r}}} \\  \\ \qquad{\longrightarrow{\sf{r =  \frac{88}{88}}}} \\  \\ \qquad{\longrightarrow{\underline{\underline{\sf{\pink{r = 1 \: cm}}}}}} \end{gathered}

Hence, the radius of cylinder is 1 cm.

———————————————————————

Now, finding the diameter of cylinder by substituting the values in the formula :

\begin{gathered} \qquad{\longrightarrow{\sf{d = 2r}}} \\  \\  \qquad{\longrightarrow{\sf{d = 2 \times 1}}} \\  \\ \qquad{\longrightarrow{\underline{\underline{\sf{\red{r = 2 \: cm}}}}}}\end{gathered}

Hence, the diameter of the base of the cylinder is 2 cm.

\rule{300}{2.5}

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