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marta [7]
3 years ago
11

Math Need to find volume Fractions

Mathematics
1 answer:
kenny6666 [7]3 years ago
6 0

V= length x width height.

5/3 x 1/4 x 3/2

15 /24 or 5/8

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State the degree and leading coefficient of each polynomial in one variable. If it is not a polynomial in one variable, explain
musickatia [10]
1.\\-6x^6-4x^5+13xy\\degree:6\\it's\ not\ a\ polynominal\ in\ one\ variable\ (13x\boxed{y})\\\\2.\\8x^5-12x^6+14x^4-9\\degree:5\\leading\ coefficient:8\\\\3.\\15x+4x^3+3x^3-5x^4\\degree:4\\leading\ coefficient:-5

4.\\(d+5)(3d-4)=3d^2-4d+15d-20\\degree:2\\leading\ coefficient:3\\\\5.\\6x^5-5x^4+2x^9-3x^2\\degree:9\\leading\ coefficient:2

3 0
3 years ago
In a doctor's waiting room, there are 14 seats in a row. Eight people are waiting to be seated. Three of the 8 are in one family
lianna [129]
There are 14 chairs and  8 people to be seated. But among the 8. three will be seated together:

So 5 people and (3) could be considered as 6 entities:

Since the order matters, we have to use permutation:

¹⁴P₆ = (14!)/(14-6)! = 2,162,160, But the family composed of 3 people can permute among them in 3! ways or 6 ways. So the total number of permutation will be ¹⁴P₆  x 3! 

2,162,160 x 6 = 12,972,960 ways.

Another way to solve this problem is as follow:

5 + (3) people are considered (for the time being) as 6 entities:

The 1st has a choice among 14 ways
The 2nd has a choice among 13 ways
The 3rd has a choice among 12 ways
The 4th has a choice among 11 ways
The 5th has a choice among 10 ways
The 6th has a choice among 9ways

So far there are 14x13x12x11x10x9 = 2,162,160 ways
But the 3 (that formed one group) could seat among themselves in 3!
or 6 ways:

Total number of permutation = 2,162,160 x 6 = 12,972,960

4 0
3 years ago
The sets of numbers 3, 4, 5 and 8, 15, 17 are Pythagorean triples. Use what you know about the Pythagorean Theorem and explain o
konstantin123 [22]

Answer:

When we have 3 numbers, like:

a, b and c.

Such that:

a < b < c.

These numbers are a Pythagorean triplet if the sum of the squares of the two smaller numbers, is equal to the square of the larger number:

a^2 + b^2 = c^2

This is equivalent to the Pythagorean Theorem, where the sum of the squares of the cathetus is equal to the hypotenuse squared.

Now that we know this, we can check if the given sets are Pythagorean triples.

1)  3, 4, 5

Here we must have that:

3^2 + 4^2 = 5^2

solving the left side we get:

3^2 + 4^2 = 9 + 16 = 25

and the right side:

5^2 = 25

Then we have the same in both sides, this means that these are Pythagorean triples.

2) 8, 15, 17

We must have that:

8^2 + 15^2 = 17^2

Solving the left side we have:

8^2 + 15^2 = 64 + 225 = 289

And in the right side we have:

17^2 = 17*17 = 289

So again, we have the same result in both sides, which means that these numbers are Pythagorean triples

4 0
2 years ago
Question 14. Two sides of a triangle have lengths of 7
babymother [125]

Answer:

8 < x < 22

Step-by-step explanation:

If x is the third side , then

difference of 2 sides < x < sum of 2 sides , that is

15 - 7 < x < 15 + 7

8 < x < 22

6 0
3 years ago
Surface area of a cube is given as 480 square inches. how long is each edge? ​
MrRissso [65]

Answer:

2880

Step-by-step explanation:

(Warning I may have this wrong, and in any way shape or form you get this question wrong i apologize)

There are 6 faces on a cube, and if each face is 480 square inches you must simply multiply 6x480.

Hope this helps :)

5 0
2 years ago
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