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Stells [14]
3 years ago
10

Jack is 12 and his sister Sophia is 16. Jack says that the relationship between his age and Sophia‘s is proportional and the con

stant of the proportionality is 12/16 do you agree
Mathematics
2 answers:
n200080 [17]3 years ago
6 0

Given that current age of Jack = 12 years

Given that current age of Sophia = 16 years

Jack says that the relationship between his age and Sophia‘s is proportional

If Jack's age is represented by y and Sophia's age by x then we can write y=kx as they are in proportion

where k is called constant of proportion

Now let's plug given ages of each that is y=12 and x=16 into y=kx to find the constant of proportionality


12=k*16

12/16=k

Which is same as the given value of constant of proportionality.

Hence Jack is right about his statement.


But if you think about practical life situation then age of both will not be in proportion

For example after 1 year Jack's age will be 13 and Sophiy's age will be 17

then constant of proportionality using new values will be 13/17

Clearly 12/16 and 13/17 are not same.

So in practical life, age of both will not in in proportion.


stiks02 [169]3 years ago
5 0

Answer:

No, it is not correct.

Step-by-step explanation:

∵ Jack's age = 12,

And, Sophia's age = 16,

So, the Sophia's age - Jack's age = 16 - 12 = 4,

If x represents the age of jack and y represents the age of Sofia,

Then y - x = 4

⇒ y = 4 + x

Which is equation of a line,

Since, if a line that shows the relation between two variable passes through the origin then the relation is proportional otherwise not,

0 = 4 + 0 ( False ),

That is, line y = 4 + x does not represents a proportional relation.

Hence, there is no proportional relation between his age and Sophia‘s is proportional.

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7 0
3 years ago
The high temperature in Fairbanks, Alaska was 15.7 °F one day. That night, the temperature fell 38.4 degrees. What was the low t
enot [183]

Answer:

-22.7

Step-by-step explanation:

Since the temperature fell, that would means that it's was cooler outside.

Hotter = Temperature goes up

Colder = Temperature goes down

15.7 - 38.4 = -22.7

3 0
3 years ago
Match the type of graph with its description.
coldgirl [10]

Answer:

1) Compares data that are in categories

2) Organises data into 4 groups of equal sizes and is often used to compare two sets of data.

3) Used to see trends in data.

4) Shows changes over time.

5) Shows the frequency of data using equal intervals with no space between the bars.

Step-by-step explanation:

1) Bar graph is used to compare data that are in categories

2) Box and whisker plot is used to organise data into 4 groups of equal size.

3) Line graph is basically used to see different trends.

4) Scatter plot is used to show changes that have occurred over time

5) Histogram is used to show the frequency of data using equal intervals with no space between the bars.

4 0
2 years ago
A trapezoid has an area of 30m^2. if all of its side lengths are tripled, what will its new area be​
Norma-Jean [14]

Answer:

270

Step-by-step explanation:

Because we do not know what the side lengths are, as long as they multiply to 30m^2, it's fine

For this question, let's just say the base is 5, and the height is 6. If we triple 5, we get 15, and if we triple 6, we get 18. 15*18=270

Now what if, the sides are not 5 and 6. Will the area still be the same? Let's find out.

10*3=30 so we can say for this answer, the base is 3, and the height is 10.

10 tripled is 30, and 3 tripled is 9. 30*9=270

So as we look at these 2 answers. we can conclude that the new area, no matter the side lengths, will be 270

Hope this helpes!

5 0
3 years ago
For each table, determine whether it shows that x and y are proportional.
myrzilka [38]

9514 1404 393

Answer:

  1. proportional, 6

  2. not proportional

Step-by-step explanation:

<u>Table 1</u>

Each y-value is 6 times the corresponding x-value, so the variables are proportional, and y = 6 times x.

<u>Table 2</u>

The ratios of y to x are 2, 4, 8, so are not the same. The values are not proportional.

8 0
2 years ago
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