2 + 3 = 8 3 + 7 = 27 4 + 5 = 32 5 + 8 = 60 6 + 7 = 72 7 + 8 = ???

Let f(x) be a continuous function such that f(1) and f'(x)-Vx3 + 6. What is the value of,f(5)? (A) 11.446 (C) 24.672 (B) 13.446

tia_tia [17]

Answer:

f(5) = 26.672 which is option D

Step-by-step explanation:

From question, f(1) = 2 and f'(x)=√(x^3 + 6)

f(5) = f(1) + (5,1)∫ f'(x) dx

Integrating using the boundary 5 and 1;

f(5) = 2 + (5,1)∫√(x^3 + 6) dx

f(5) = 2 + 24.672

So f(5) = 26.672

7 0

3 years ago

A software designer is mapping the streets for a new racing game. all of the streets are depicted as either perpendicular or par

ElenaW [278]

The equation of the central street PQ is -1.5x - 3.5y = -31.5 option (b) is correct.

<h3>What is a straight line?</h3>

A straight line is a combination of endless points joined on both sides of the point.

We have a straight line:

$-7x+3y=-21.5$

Convert it to the general form given below:

$\rm y=mx+c$

$\rm 3y=-21.5+7x\\\\ \rm y = \frac{-21.5}{3}+\frac{7}{3}x$ or

$\rm y = \frac{7}{3}x-\frac{21.5}{3}$

$m = \frac{7}{3}$ (Slope of AB line)

For the slope(m') of the PQ line:

$\rm m'=-\frac{1}{m}$ ( because AB and PQ are perpendicular to each other)

$\rm m' = -\frac{3}{7}$

We know the:

$\rm (y-y')=m'(x-x')$

Where (x', y') = (7, 6), we get:

$\rm (y-6)=-\frac{3}{7} (x-7)$

$\rm 7(y-6)=-3 (x-7)\\\\\rm 7y-42= -3x+21\\\\\rm 7y= -3x+21+42\\\\\rm 3x+7y=63$

$\rm -1.5x-3.5y=-31.5$ (multiply by -1/2 on both sides)

Thus, the equation of the central street PQ is -1.5x - 3.5y = -31.5

Learn more about the straight line.

brainly.com/question/3493733

6 0

2 years ago

See attachment the problem can be found in there

zloy xaker [14]

Answer:

$\frac{ - 2 {x}^{2} + 19x + 3 }{3 {x} (4x^{2} - 9 )}$

Step-by-step explanation:

$\frac{5}{6 {x}^{2} + 9x} + \frac{1}{2x - 3} - \frac{2}{3x} \\ \\ = \frac{5}{3x(2 {x} + 3)} + \frac{1}{2x - 3} - \frac{2}{3x} \\ \\ = \frac{5(2x - 3) + 1 \times 3x(2x + 3)}{3x(2 {x} + 3)(2x - 3)} - \frac{2}{3x} \\ \\ = \frac{10x - 15 + 6 {x}^{2} + 9x}{3x((2 {x} ) ^{2} - {3}^{2} )} - \frac{2}{3x} \\ \\ = \frac{6 {x}^{2} + 19x - 15}{3x(4x^{2} - 9 )} - \frac{2}{3x} \\ \\ = \frac{3x(6 {x}^{2} + 19x - 15) - 2 \times 3x(4x^{2} - 9 )}{3x(4x^{2} - 9 ) \times 3x} \\ \\ = \frac{18{x}^{3} + 57 {x}^{2} - 45x - 24x^{3} + 54x }{3x(4x^{2} - 9 ) \times 3x} \\ \\ = \frac{ - 6 {x}^{3} + 57 {x}^{2} + 9x }{9 {x}^{2} (4x^{2} - 9 )} \\ \\ = \frac{ 3x(- 2 {x}^{2} + 19x + 3) }{9 {x}^{2} (4x^{2} - 9 )} \\ \\ \huge \orange{ \boxed{= \frac{ - 2 {x}^{2} + 19x + 3 }{3 {x} (4x^{2} - 9 )} }}$

7 0

3 years ago

In the function y = 15.00x + 5, y represents the cost of a ticket to the fair and x represents the number of tickets purchased.

kkurt [141]

For every ticket purchased, the cost will increase by $15.00 because x indicates that $15 is the unit rate for each ticket.

4 0

3 years ago

Margaret bought 1,575 grams of rice. how many kg of rice is that?

bearhunter [10]

1 kg = 1000 grams

? kg = 1575 grams

1.575 kg = 1575 grams

1,575 grams is 1.575 kilograms.

6 0

4 years ago

2 + 3 = 83 + 7 = 274 + 5 = 325 + 8 = 606 + 7 = 727 + 8 = ???