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Aneli [31]
3 years ago
5

Please help asap show work please thank you

Mathematics
2 answers:
gizmo_the_mogwai [7]3 years ago
5 0
#3 is a triangular pyramid because triangular pyramids have 4 triangular faces.
#4 is a cube because there are 6 square faces.
#5 is a triangular prism. It has 2 triangular faces and 3 rectangular faces.
#6 is a rectangular prism. It has 2 square faces and 4 rectangular faces.
(If you don't know what the figure of the net is, resketch it on another piece of paper, cut it out, and form it.)

Hope this helps,
Loafly
OLEGan [10]3 years ago
4 0
U have to draw the same shape to the side
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3 years ago
I need to get the left side to equal the right side. Keeping the right side alone and not changing it.
likoan [24]

<u>To prove the trigonometric equation:</u>

\sin ^{3} x+\cos ^{3} x=(\sin x+\cos x)(1-\sin x \cos x)

RHS=(\sin x+\cos x)(1-\sin x \cos x)

We know that \sin^2x +\cos^2x=1, substitute this in place of 1.

       =(\sin x+\cos x)(\sin^2x +\cos^2x-\sin x \cos x)

Multiply each term of the first term with each term of the 2nd term.

       =\sin^3x + \sin x \cos^2x-\sin^2 x \cos x+\cos x \sin^2 x + \cos^3 x-\sin x\cos^2 x

Group like terms together.

       =\sin^3x +( \sin x \cos^2x-\sin x\cos^2 x)+(\cos x \sin^2 x-\sin^2 x \cos x) + \cos^3 x

       =\sin^3x +( 0)+(0) + \cos^3 x

       =\sin^3x + \cos^3 x

       = LHS

RHS = LHS

\sin ^{3} x+\cos ^{3} x=(\sin x+\cos x)(1-\sin x \cos x)

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