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Arlecino [84]
3 years ago
9

When should you use an electronic spreadsheet

Computers and Technology
1 answer:
nadezda [96]3 years ago
6 0

Answer:

An electronic spreadsheet can be used to perform numerical calculations automatically

Explanation:

An electronic spreadsheet can be used to perform numerical calculations automatically. This spreadsheets are set up in the form of a table with rows and columns.

Data is stored in a cell formed as a result of intersection of each row and column.

Their primary purpose is to organize and categorize data into a logical format. This data then can be used to organize and grow the business.

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Computer A has an overall CPI of 1.3 and can be run at a clock rate of 600 MHz. Computer B has a CPI of 2.5 and can be run at a
kirill115 [55]

Answer:

Check the explanation

Explanation:

CPI means Clock cycle per Instruction

given Clock rate 600 MHz then clock time is Cー 1.67nSec clockrate 600M

Execution time is given by following Formula.

Execution Time(CPU time) = CPI*Instruction Count * clock time = \frac{CPI*Instruction Count}{ClockRate}

a)

for system A CPU time is 1.3 * 100, 000 600 106

= 216.67 micro sec.

b)

for system B CPU time is =\frac{2.5*100,000}{750*10^6}

= 333.33 micro sec

c) Since the system B is slower than system A, So the system A executes the given program in less time

Hence take CPU execution time of system B as CPU time of System A.

therefore

216.67 micro = =\frac{2.5*Instruction}{750*10^6}

Instructions = 216.67*750/2.5

= 65001

hence 65001 instruction are needed for executing program By system B. to complete the program as fast as system A

3 0
3 years ago
Pls someone help me with these four questions
ipn [44]

Answer:

16. Grace Hopper. 1959.

8 0
3 years ago
Adobe Indesign project 4 museum indesign file. The instructions are 70 pages long I cant sit still long enough to read them
Alchen [17]

Answer:

? Read on to learn about the possible reasons and resolutions. ... Check whether you have the latest update installed for InDesign. ... InDesign cannot open the file when your system does not have enough memory ... Copy page elements into a new document.

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4 0
3 years ago
Wireshark capture files, like the DemoCapturepcap file found in this lab, have a __________ extension, which stands for packet c
grin007 [14]

Answer:

The answer is ".pcapng"

Explanation:

Wireshark format includes a "dump" with data packets, which is collected over a channel and sometimes a common folder to store, that data in the PCAP Next Iteration file system.

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5 0
3 years ago
Create an array to hold the rainfall values. Create a 2nd parallel array (as a constant) to hold the abbreviated names of the mo
Zarrin [17]

Answer:

#include <stdio.h>

int main()

{

//variable declaration

int low, high;

float lowRain, highRain, total, avg;

 

//array declaration

float rainfall[13];

char monthName[13][10] = {"", "Jan", "Feb", "Mar", "Apr", "May", "Jun", "Jul", "Aug", "Sep", "Oct", "Nov", "Dec"};

//get user input

for(int i=1; i<=12; i++)

{

printf("Enter the rainfall (in inches) for %s: ", monthName[i]);

scanf("%f", &rainfall[i]);

}

 

//display the monthly rainfall

printf("\nThe rainfall that was entered was:\n");

for(int i = 1; i<=6; i++)

printf("%s ", monthName[i]);

printf("\n");

for(int i = 1; i<=6; i++)

printf("%.1f ", rainfall[i]);

printf("\n");

for(int i = 7; i<=12; i++)

printf("%s ", monthName[i]);

printf("\n");

for(int i = 7; i<=12; i++)

printf("%.1f ", rainfall[i]);

 

//variable initialization

low = 1;

high = 1;

lowRain = rainfall[1];

highRain = rainfall[1];

total = 0;

 

//calculate the lowest, highest and averaage rainfall

for(int i=1; i<=12; i++)

{

if(lowRain>rainfall[i])

{

lowRain = rainfall[i];

low = i;

}

if(highRain<rainfall[i])

{

highRain = rainfall[i];

high = i;

}

total = total + rainfall[i];

}

 

avg = total / 12;

 

//display the result

printf("\n\nThe total rain that fell was %.1f inches", total);

printf("\nThe average monthly rainfall was %.1f inches.", avg);

printf("\nThe lowest monthly rainfall was %.1f inches in %s.", rainfall[low], monthName[low]);

printf("\nThe highest monthly rainfall was %.1f inches in %s.", rainfall[high], monthName[high]);

return 0;

}

4 0
3 years ago
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