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tatyana61 [14]
4 years ago
11

What is subtracting fractions from mixed numbers for grade 4

Mathematics
1 answer:
Slav-nsk [51]4 years ago
4 0

Answer:

Step-by-step explanation:

You subtract straight across.

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Find the solutions to the equation below.
Volgvan

Answer:

A and C

Step-by-step explanation:

Move all terms to the left side and set equal to zero. Then set each factor equal to zero

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3 years ago
What is negative 6 + 5 and 1/4?=
Leokris [45]

Answer:

-0.75

Step-by-step explanation:

3 0
3 years ago
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If you roll two fair six-sided dice, what is the probability that both dice show an odd number?
madam [21]
There's a 25 percent chance that both of them land on an odd number.
4 0
4 years ago
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Which of these statements is correct?
mariarad [96]

Answer:

The answer to your question is the third choice.

Step-by-step explanation:

a)          6x - 5y = 8

           12x - 10y = 16

We observe that these lines are the same so they have infinite solutions.

b)

            7x + 2y = 6

           14x + 4y = 16

These lines are parallel because they have the same slope, so they do not cross, there is no solution.

c)

             8x - 3y = 10

            16x - 6y = 22

These lines are parallel because they have the same slope, so they do not cross, there is no solution.

d)

            9x + 6y = 14

           18x + 12y = 26

These lines are parallel because they have the same slope, so they do not cross, they do not have an infinite number of solutions.

3 0
3 years ago
Read 2 more answers
Question below
Ksivusya [100]

Answer:

m \times H=\left[\begin{array}{c c c}\boxed{-9} & \boxed{36} & \boxed{-\dfrac{9}{2}}\end{array}\right]

Step-by-step explanation:

<u>Calculate the value of m</u>

Given:

3\left[\begin{array}{c c}-1 & 2 \\4 & 8\end{array}\right]=\dfrac{2}{3}m \times \left[\begin{array}{c c}-1 & 2 \\4 & 8\end{array}\right]

Therefore:

\implies 3=\dfrac{2}{3}m

\implies m=3 \times \dfrac{3}{2}

\implies m=\dfrac{9}{2}

<u>Calculate the value of H</u>

Given:

\left(H+ \left[\begin{array}{c c c}1 & 4 & -2\end{array}\right]\right)+\left[\begin{array}{c c c}3 & 2 & -6\end{array}\right]=\left[\begin{array}{c c c}-2 & 8 & -1\end{array}\right]+\left(\left[\begin{array}{c c c}1 & 4 & -2\end{array}\right]+\left[\begin{array}{c c c}3 & 2 & -6\end{array}\right]\right)

Therefore:

\implies H= \left[\begin{array}{c c c}-2 & 8 & -1\end{array}\right]

<u />

<u>Calculating m × H</u>

<u />

<u />\implies m \times H=\dfrac{9}{2} \times \left[\begin{array}{c c c}-2 & 8 & -1\end{array}\right]

<u />\implies m \times H=\left[\begin{array}{c c c}\dfrac{9}{2}(-2) & \dfrac{9}{2}(8) & \dfrac{9}{2}(-1)\end{array}\right]

\implies m \times H=\left[\begin{array}{c c c}-9 & 36 & -\dfrac{9}{2}\end{array}\right]<u />

7 0
2 years ago
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