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statuscvo [17]
3 years ago
7

What is the value of R?

Mathematics
1 answer:
attashe74 [19]3 years ago
8 0

r=5

10(5)-20 = 30

6(5) = 30

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-10 +log3 (n+3)= -10
Rufina [12.5K]

Answer:

n= -3 or in exact form: N= - log27/log3

Step-by-step explanation:

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4 years ago
Roger had $1200. He bought a phone with 0.4 of the money and a helmet with 0.5 of the remaining money. What is the amount of mon
Paul [167]

Answer:

the remaining money is $1189.22

Step-by-step explanation:

7 0
3 years ago
Please help i have no clue what to do <br> i suck at math
beks73 [17]
The first one is 63.9 and the second should be 116.1
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The perimeter cf a rectangle i: 56 inches" the ratio of the length of the width is 6 : 1. Find the length and the width.
sergejj [24]

Answer: Length = 24; width =4

Step-by-step explanation

Since the ratio of the length to width is 6:1

Let the length  be represented as  6x

And the width be  = x

Such that that the Perimeter of the rectangle which is  

Perimeter = 2(length + width)  becomes

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8 0
3 years ago
Evaluate the expression
larisa86 [58]

Answer:

12-[20-2(6^2\div3\times2^2)]=88

Step-by-step explanation:

So we have the expression:

12-[20-2(6^2\div3\times2^2)]

Recall the order of operations or PEMDAS:

P: Operations within parentheses must be done first. On a side note, do parentheses before brackets.

E: Within the parentheses, if exponents are present, do them before all other operations.

M/D: Multiplication and division next, whichever comes first.

A/S: Addition and subtraction next, whichever comes first.

(Note: This is how the order of operations is traditionally taught and how it was to me. If this is different for you, I do apologize. However, the answer should be the same.)

Thus, we should do the operations inside the parentheses first. Therefore:

12-[20-2(6^2\div3\times2^2)]

The parentheses is:

(6^2\div3\times2^2)

Square the 6 and the 4:

(36\div3\times4)

Do the operations from left to right. 36 divided by 3 is 12. 12 times 4 is 48:

(36\div3\times4)\\=(12\times4)\\=48

Therefore, the original equation is now:

12-[20-2(6^2\div3\times2^2)]\\=12- [20-2(48)]

Multiply with the brackets:

=12-[20-96]

Subtract with the brackets:

=12-[-76]

Two negatives make a positive. Add:

=12+76=88

Therefore:

12-[20-2(6^2\div3\times2^2)]=88

3 0
3 years ago
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