Answer:
<h3>0.27</h3>
Explanation:
The question is incomplete. Here is the complete question:
<em>You are pushing a 13.3 kg lawn mower across the lawn with a force of 200 N. What is the value of the coefficient of friction between the mower and the grass if the mower moves with a constant velocity? The force is applied downward at an angle of 65° with the horizontal.</em>
<em></em>
According to Newton's second law of motion:
Fapp is the applied force = 200N
Ff is the frictional force
is the coefficient of friction between the mower and the grass
R is the reaction
m is the mass of the object
ax is the acceleration
Given
R = mg = 13.3*9.8
R = 130.34N
m = 13.3kg
ax = 0m/s² (constant velocity)
Fapp = 200N
Substitute the given parameters into the formula and get the coefficient of friction as shown;
Recall that:
<em>Hence the coefficient of friction between the mower and the grass is 0.27</em>
Answer:
0.9 N.
Explanation:
Mass (m) of car = 150 g
Initial velocity (u) = 0 m/s
Final velocity (v) = 24 m/s
Time (t) = 4 s
Next, we shall determine the acceleration of the car. This can be obtained as follow:
Initial velocity (u) = 0 m/s
Final velocity (v) = 24 m/s
Time (t) = 4 s
Acceleration (a) =?
v = u + at
24 = 0 + (a × 4)
24 = 0 + 4a
24 = 4a
Divide both side by 4
a = 24 /4
a = 6 m/s²
Thus, the acceleration of the car is 6 m/s²
Next, we shall convert 150 g to Kg. This can be obtained as follow:
1000 g = 1 kg
Therefore,
150 g = 150 g × 1 Kg / 1000 g
150 g = 0.15 Kg
Thus, 150 g is equivalent to 0.15 Kg
Finally, we shall determine the force of the car as follow:
Mass (m) of car = 0.15 Kg
Acceleration (a) of car = 6 m/s²
Force (F) of car =?
F = m × a
F = 0.15 × 6
F = 0.9 N
Therefore, the force of the car is 0.9 N.
Answer:
Anatomy is the study of the structure and relationship between body parts.
Physiology is the study of the function of body parts and the body as a whole.
Explanation:
Relative age is the age of a rock layer (or the fossils it contains) compared to other layers. It can be determined by looking at the position of rock layers. Absolute age is the numeric age of a layer of rocks or fossils. Absolute age can be determined by using radiometric dating.