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VikaD [51]
2 years ago
11

Jorge is sending a large image file to a friend as part of a shared classroom project. Which of the following is most likely tru

e if Jorge opts to compress the image before sending it? A. The image can no longer be represented using bits. B. The image will have been converted into an analog form. C. The image will require more pixels to display it on the screen. D. The image will require fewer bits in order to be represented.
Computers and Technology
1 answer:
madreJ [45]2 years ago
5 0

Answer:

D. The image will require fewer bits in order to be represented.

Explanation:

Lossy compression algorithms are typically better than lossless compression algorithms at reducing the number of bits needed to represent a piece of data.

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Driving is expensive. Write a program with two inputs, a car's miles/gallon and the cost of gas/gallon both represented as doubl
Nataly_w [17]

Answer:33

Explanation:

6 0
2 years ago
6.23 LAB: Convert to binary - functions Instructor note: This is a lab from a previous chapter that now requires the use of a fu
Kitty [74]

Answer:

The program in Python is as follows:

import math

def integer_to_reverse_binary(integer_value):

   remainder = ""

   while integer_value>=1:

       remainder+=str(integer_value % 2)

       integer_value=math.floor(integer_value/2)

   reverse_string(remainder)

def reverse_string(input_string):

   binaryOutput=""

   for i in range(len(input_string)-1,-1,-1):

       binaryOutput = binaryOutput + input_string[i]

   print(binaryOutput)

integer_value = int(input("Enter a Number : "))

integer_to_reverse_binary(integer_value)

Explanation:

This imports the math module

import math

This defines the integer_to_reverse_binary function

def integer_to_reverse_binary(integer_value):

This initializes the remainder to an empty string

   remainder = ""

This loop is repeated while the integer input is greater than or equal to 1

   while integer_value>=1:

This calculates the remainder after the integer value is divided by 2

       remainder+=str(integer_value % 2)

This gets the floor division of the integer input by 2

       integer_value=math.floor(integer_value/2)

This passes the remainder to the reverse_string function

   reverse_string(remainder)

The reverse_string function begins here

def reverse_string(input_string):

This initializes the binaryOutput to an empty string

   binaryOutput=""

This iterates through the input string i.e. the string of the remainders

   for i in range(len(input_string)-1,-1,-1):

This reverses the input string

       binaryOutput = binaryOutput + input_string[i]

This prints the binary output

   print(binaryOutput)

<u>The main begins here</u>

This gets input for integer_value

integer_value = int(input("Enter a Number : "))

This passes the integer value to the integer_to_reverse_binary function

integer_to_reverse_binary(integer_value)

3 0
2 years ago
Nosql is a great technology for storing well-structured data. <br> a. True <br> b. False
mash [69]
I'd say False

NoSQL or the non-rational databases are document oriented and distributed. Unlike the SQL or the relational databases which are structured, NoSQL deals with a huge amount of unstructured data and offer greater flexibility. NoSQL are more like file folders, gathering related information of all types.



3 0
3 years ago
In which area is composing for games different from composing for movies?
kondaur [170]

Answer: royalties earned

Explanation:

In areas such as the looping scores, temp tracks and adaptive scores, there are similarities when composing for games and when composing for movies.

The area where there is difference when composing for games and composing for movies is the royalties earned. The interest that is earned on royalties for both cases are different.

8 0
3 years ago
In Java, write a AllDigitsOdd program that has a method called allDigitsOdd that takes an integer and returns whether every digi
yan [13]

Answer:

Hi there! The solution for this problem can be implemented a number of ways. Please find my solution below along with the explanation.

Explanation:

The prompts are fairly easily implemented using the Scanner class in Java for user input. In the allDigitsOdd function, we can perform a Math operation on the number being passed into the function to determine the number of digits in the number. We use the log10 function to do this and convert the double value returned to int. This is calculated in the code below as:  "(int)(Math.log10(number) + 1); ". Once we have the number of digits, we write a simple loop to iterate over each digit and perform a modulus function on it to determine if the digit is odd or even. I have declared 2 variables call odd and even that get incremented if the mod function (%) returns a 1 or a 0 respectively. Finally, the result is displayed on the screen.

AllDigitsOdd.java

import java.util.Scanner;

import java.lang.Math;

public class AllDigitsOdd {

 public static void main(String args[]) {

   // print main menu for user selection

   System.out.println("Please enter a number");

   Scanner scan = new Scanner(System.in);

   int selection = scan.nextInt();

   if (allDigitsOdd(selection)) {

     System.out.println("All numbers are odd");

   } else {

     System.out.println("All numbers are not odd");

   }

 }

 public static boolean allDigitsOdd(int number) {

   int digits = (int)(Math.log10(number) + 1);

   int even = 0;

   int odd = 0;

   for (int index = 1; index <= digits; index++) {

       if ((int)(number / Math.pow(10, index - 1)) % 10 % 2 == 0) {

         even += 1;

       } else {

         odd += 1;

       }

   }

   if (even == 0 && odd > 0) {

     return true;

   } else {

     return false;

     //if (odd > 0 && even == 0) {

     //  return true;

     //}

   }

 }

}

8 0
3 years ago
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