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2 years ago

Determine the product of -8 and -4.

Mathematics

1 answer:

Romashka-Z-Leto [24]2 years ago

3 0

-8 * -4 = 32

Just multiply both numbers and negatives cancel

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4x + 12 = -7y -y + 12 = 4x Solve with elimination

statuscvo [17]

Take the second equation and flip it around so the y on the left ends up on the right and the 4x on the right ends up on the left. This makes all negatives positive and all positives negative. -4x + 12 = y

Then add the first equation to the second equation
4x +12 = -7y
-4x + 12 = y this eliminates the x's
24 = - 6y then divide by - 6
- 6 - 6
- 4 = y

So if you know that y = negative 4, you can substitute into either equation. I pick the second one because I am a lazy person.
-y + 12 = 4 x
-(-4) + 12 = 4 x combine your numbers
 16 = 4 x then divide by 4
 4 = x
So your solution is: x = 4 and y = -4 or this is also written (4, -4)

Does that work for you?

4 0

3 years ago

Read 2 more answers

HELPP! Geometry volume practice

GarryVolchara [31]

Answer:

Step-by-step explanation:

the height is 80 m

hope that helps

7 0

2 years ago

Evaluate the following integrals: 1. Z x 4 ln x dx 2. Z arcsin y dy 3. Z e −θ cos(3θ) dθ 4. Z 1 0 x 3 √ 4 + x 2 dx 5. Z π/8 0 co

Zigmanuir [339]

Answer:

The integrals was calculated.

Step-by-step explanation:

We calculate integrals, and we get:

1) ∫ x^4 ln(x) dx=\frac{x^5 · ln(x)}{5} - \frac{x^5}{25}

2) ∫ arcsin(y) dy= y arcsin(y)+\sqrt{1-y²}

3) ∫ e^{-θ} cos(3θ) dθ = \frac{e^{-θ} ( 3sin(3θ)-cos(3θ) )}{10}

4) \int\limits^1_0 {x^3 · \sqrt{4+x^2} } \, dx = \frac{x²(x²+4)^{3/2}}{5} - \frac{8(x²+4)^{3/2}}{15} = \frac{64}{15} - \frac{5^{3/2}}{3}

5) \int\limits^{π/8}_0 {cos^4 (2x) } \, dx =\frac{sin(8x} + 8sin(4x)+24x}{6}=

=\frac{3π+8}{64}

6) ∫ sin^3 (x) dx = \frac{cos^3 (x)}{3} - cos x

7) ∫ sec^4 (x) tan^3 (x) dx = \frac{tan^6(x)}{6} + \frac{tan^4(x)}{4}

8) ∫ tan^5 (x) sec(x) dx = \frac{sec^5 (x)}{5} -\frac{2sec^3 (x)}{3}+ sec x

6 0

3 years ago

Need the answer the question is in the picture

SOVA2 [1]

Answer:

d= -5

Step-by-step explanation:

6 0

2 years ago

If g(x) = {(4, -5), (-3, 2), (-6, 1), (1,0)}, which set of ordered pairs represents

Ket [755]

Answer:

The inverse of g(x) is {(-5, 4), (2, -3), (1, -6), (0, 1)} ⇒ (A)

Step-by-step explanation:

To find the inverse of a function switch x and y

Example:

If f(x) = {(1, 2), (-4, 5), (0, 0)}

To find its inverse switch x and y in each ordered pair

The inverse of f(x) = {(2, 1), (5, -4), (0, 0)}

Let us do the same with our question

∵ g(x) = {(4, -5), (-3, 2), (-6, 1), (1, 0)}

→ Switch x and y coordinates in all ordered pair

∴ The inverse of g(x) = {(-5, 4), (2, -3), (1, -6), (0, 1)}

Look at the answer to find the correct choice

It is (A)

6 0

2 years ago