A runner is traveling at a constant rate of 8 meters per second. How long does it take for the runner to travel 100 meters?
1 answer:
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AC=x, BC=x√3, AB is a hypotenuse (look at the pic below)
x√3>x, consequently ∠B<∠A and we have to find cosB, which is (x√3)/AB.
<em>Let's find AB:</em>
AB=√(x²+(x√3)²)=√(x²+3x²)=√(4x²)=2x
<em>Thus, cosB is:</em>
cosB=(x√3)/(2x)=√3/2
x√3>x, consequently ∠B<∠A and we have to find cosB, which is (x√3)/AB.
<em>Let's find AB:</em>
AB=√(x²+(x√3)²)=√(x²+3x²)=√(4x²)=2x
<em>Thus, cosB is:</em>
cosB=(x√3)/(2x)=√3/2