Answer:
Opt. D.
Step-by-step explanation:
To solve this problem we need to focus our attention in the abs(x-1) function,
If x>1, then abs|x-1|= x-1, if x<1 then abs|x-1|= 1-x. And in the two intervals, the function opens upwards.
But our function has -3 multiplying abs|x-1|, This means that our function opens downward.
The vertex point can be found when x=1, since abs(x-1)=0. this gives f(1)=12
Answer: -6
Step-by-step explanation: 7 + -6 = 1
:\
Answer:
the answer is 131.4
Step-by-step explanation:
32.85/3= 10.95
10.95×12= 131.4
Answer:
No ;
Step-by-step explanation:
Given ;
s2 = 10 ; n2 = 10 ; s1 = 12 ; n1 = 12
Hypothesis :
H0 : σ1² = σ2²
H1 : σ1² ≠ σ2²
The test statistic :
Ftest = s1² / s2² = 12² / 10² = 144 / 100 = 1.44
The Pvalue using the Pvalue from Ftest calculator :
Numerator df = 12 - 1 = 11
Denominator df = 10 - 1 = 9
Pvalue = 0.2969
At α = 0.1
If Pvalue > α ; Fail to reject H0
0.2969 > 0.1 ; Hence, we fail to reject the Null
Hence, we cannot conclude that variation exists
Answer:
)x + 5)(x - 5)
Step-by-step explanation:
x² - 25 ← is a difference of squares and factors in general as
a² - b² = (a + b)(a - b), thus
x² - 25 = x² - 5² = (x + 5)(x - 5)
