Answer:
(2c³ -20c² -10c) -(c² -40c +100)
Step-by-step explanation:
<u>Profit</u>
For a problem involving cost, revenue, and profit, you are expected to know that <em>profit is the difference between revenue and cost</em>. That is, if it costs you $2 to make a necklace you sell for $10, your profit is $10 -2 = $8.
<u>Problem</u>
The problem gives you polynomial expressions for revenue and cost, and asks you to combine them to make an expression for profit. In this first part, we simply show <em>how</em> we will combine them. (We presume a later part of the question will ask you to simplify the result.)
profit = revenue - cost
Substituting the given expressions, we have ...
profit = (2c³ -20c² -10c) -(c² -40c +100) . . . . . matches last choice
Answer:
Step-by-step explanation:
Given
![6\ [\ ]\ (\ 3\ [\ ]\ 1\ )\ [\ ]\ 5\ [\ ]\ 1\ =\ 17](https://tex.z-dn.net/?f=6%5C%20%5B%5C%20%5D%5C%20%28%5C%203%5C%20%5B%5C%20%5D%5C%201%5C%20%29%5C%20%5B%5C%20%5D%5C%205%5C%20%5B%5C%20%5D%5C%201%5C%20%3D%5C%2017)
Required
Fill in the box with +,-, x, and ⌯ (once each)
This question is solved using trial by error approach.
After some tests, the solution that matches the equation is:
Answer:
50
Step-by-step explanation:
100 into 2 parts is 50
Puting it into the quadrait equation ((-b+-[b^2-4ac]^(1/2)/2a), we get that x= 31^(1/2)-5 or 31^(1/2)+5
So I’m going to solve this using algebra OK?
So what you do is take the first integer as X.
Then we know that x(the first number) + X+2(the second number) is 288 right?
So we solve that saying x+x+2=288.
So 2X+2=288
2X+2-2=288-2 right?
So 2X=286.
So x is 286/2 right?
So x is 143.
Now the first number is 143 right?
So the second number should be 143+2 so 145.
I know they are not even but these are the solutions.
I don’t think there are any consecutive even numbers that add up to 288
