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Illusion [34]
3 years ago
13

Imagine that you are conducting a poll to determine the percentage of adults who gamble at least once a month. As your sample si

ze increases (let us say from 100 to 400 cases), which of the following becomes true?
A. Confidence interval becomes wider
B. Margin of error becomes smaller
C. Amount of sampling error increases
D. Margin of error increases
Mathematics
1 answer:
Orlov [11]3 years ago
5 0

Answer:

Option B) Margin of error becomes smaller

Step-by-step explanation:

We are given the following information in the question:

A poll to determine the percentage of adults who gamble at least once a month.

We have to find what happens to the confidence interval as the sample size increases.

Margin of error =

\text{Critical Value}\times \displaystyle\frac{\sigma}{\sqrt{n}}

Confidence interval:

\mu \pm \text{Margin of error}

As the sample size increases, the margin of error decreases.

As the margin of error decreases the width of the confidence interval decreases.

Option B) Margin of error becomes smaller

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Use the Euclidean Algorithm to compute the greatest common divisors indicated. (a) gcd(20, 12) (b) gcd(100, 36) (c) gcd(207, 496
coldgirl [10]

Answer:

(a) gcd(20, 12)=4

(b) gcd(100, 36)=4

(c) gcd(496,207 )=1

Step-by-step explanation:

The Euclidean algorithm is an efficient method for computing the greatest common divisor of two integers, without explicitly factoring the two integers.

The Euclidean algorithm solves the problem:

<em>                                   Given integers </em>a, b<em>, find </em>d=gcd(a,b)<em />

Here is an outline of the steps:

  1. Let a=x, b=y.
  2. Given x, y, use the division algorithm to write x=yq+r.
  3. If r=0, stop and output y; this is the gcd of a, b.
  4. If r\neq 0, replace (x,y) by (y,r). Go to step 2.

The division algorithm is an algorithm in which given 2 integers N and D, it computes their quotient Q and remainder R.

Let's say we have to divide N (dividend) by D (divisor). We will take the following steps:

Step 1: Subtract D from N repeatedly.

Step 2: The resulting number is known as the remainder R, and the number of times that D is subtracted is called the quotient Q.

(a) To find gcd(20, 12) we apply the Euclidean algorithm:

20 = 12\cdot 1 + 8\\ 12 = 8\cdot 1 + 4\\ 8 = 4\cdot 2 + 0

The process stops since we reached 0, and we obtain gcd(20, 12)=4.

(b) To find gcd(100, 36) we apply the Euclidean algorithm:

100 = 36\cdot 2 + 28\\ 36 = 28\cdot1 + 8\\ 28 = 8\cdot 3 + 4\\ 8 = 4\cdot 2 + 0

The process stops since we reached 0, and we obtain gcd(100, 36)=4.

(c) To find gcd(496,207 ) we apply the Euclidean algorithm:

496 = 207\cdot 2 + 82\\ 207 = 82\cdot 2 + 43\\ 82 = 43\cdot 1 + 39\\ 43 = 39\cdot 1 + 4\\ 39 = 4\cdot 9 + 3\\ 4 = 3\cdot 1 + 1\\ 3 = 1\cdot 3 + 0

The process stops since we reached 0, and we obtain gcd(496,207 )=1.

3 0
3 years ago
What is the value of n that would make the following radical expression true?
viktelen [127]

Answer: 3

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
Please see the screenshot.
sesenic [268]

Answer:

the answer is c, (-10,4) and the radius is 10

Step-by-step explanation:

Hope this helps!❆

6 0
3 years ago
Find the average rate of change of f(x) = -x² + 5x+2 from x=3 to x=6.
ivolga24 [154]

9514 1404 393

Answer:

  -4

Step-by-step explanation:

The points at the ends of the interval are ...

  (3, f(3)) = (3, 8)

  (6, f(6)) = (6, -4)

The slope is given by the slope formula:

  m = (y2 -y1)/(x2 -x1)

  m = (-4 -8)/(6 -3) = -12/3 = -4

The average rate of change is -4.

6 0
3 years ago
What’s the correct answer for this?
Mice21 [21]

。☆✼★ ━━━━━━━━━━━━━━  ☾  

First, you'd work out the centre value

It would be the opposite value to what is in the brackets

Thus, the centre value is (2, -4)

Plot this value on a graph

In order to find the radius, you must square root the 25

Thus, the radius would be 5

Plot some points with a radius of 5 from the centre and then draw the circle

Have A Nice Day ❤    

Stay Brainly! ヅ    

- Ally ✧    

。☆✼★ ━━━━━━━━━━━━━━  ☾

8 0
3 years ago
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