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Illusion [34]
4 years ago
13

Imagine that you are conducting a poll to determine the percentage of adults who gamble at least once a month. As your sample si

ze increases (let us say from 100 to 400 cases), which of the following becomes true?
A. Confidence interval becomes wider
B. Margin of error becomes smaller
C. Amount of sampling error increases
D. Margin of error increases
Mathematics
1 answer:
Orlov [11]4 years ago
5 0

Answer:

Option B) Margin of error becomes smaller

Step-by-step explanation:

We are given the following information in the question:

A poll to determine the percentage of adults who gamble at least once a month.

We have to find what happens to the confidence interval as the sample size increases.

Margin of error =

\text{Critical Value}\times \displaystyle\frac{\sigma}{\sqrt{n}}

Confidence interval:

\mu \pm \text{Margin of error}

As the sample size increases, the margin of error decreases.

As the margin of error decreases the width of the confidence interval decreases.

Option B) Margin of error becomes smaller

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GalinKa [24]

Answer:

The correct answer is 18

the correct expression is (4n+6)

Step-by-step explanation:

let the number be n

therefore  if he is required to multiply n by 4 and added to 6 we have

(4n+6)= 0-----1

given that he did otherwise by adding 6 to n and multiply by 4 we have

(n+6)4= 36------2

Firstly we need to solve for n in equation 2

4n+24= 36\\4n= 36-24\\4n= 12\\

Dividing both sides by 4 we have

n= \frac{12}{4\\}\\n= 3

In order to solve for the correct answer let us input n=3 in equation 1 we have

=(4n+6)= 0-------1\\=(4*3+6)= 0\\=(12+6)=0\\= 18

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PLS HALP ASAP
Oksanka [162]

Answer:

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2 years ago
Heather bought a CD on sale for $11 and a book that cost $14 the sales tax rate is 5% how much tax did Heather pay for both item
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Given the following chemical reaction:
Marizza181 [45]

Answer:

The answer to your question is 12 moles of water.

Step-by-step explanation:

Reaction

                            2 O₂   +   CH₄     ⇒     CO₂    +   2 H₂O

If Oxygen is in excess, then the limiting reactant is methane and we calculate the moles of water produced considering the moles of methane.

                          1 mol of methane --------------  2 moles of water

                           6 moles of methane ---------   x

                           x = (6 x 2) / 1

                           x = 12 moles of water

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3 years ago
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