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stealth61 [152]
3 years ago
10

University Theater sold 465 tickets for a play. Tickets cost $23 per adult and $13 per senior citizen. If total receipts were $7

145, how many senior citizen tickets were sold?
Mathematics
1 answer:
liq [111]3 years ago
8 0

<u>Answer:</u>

355 senior citizen tickets were sold.

<u>Step-by-step explanation:</u>

Assuming a to the the ticket of adults and s to be the ticket of senior citizens, we can write two equations as:

a +s=465 --- (1)

23a+13s=7145 --- (2)

From equation 1, a=465-s.

Substitute a in equation 2 to get:

23 (465-s) + 13s = 7145

10695 - 23s +13s =7145

-10s = -3550

s = 355

Therefore, there were 355 senior citizen tickets sold.

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Write the ordered pair that corresponds to point D and point H
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What is the slope of a line parallel to the line with equation y = 5x – 2
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A:5

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3 years ago
June has $1.95 in dimes and nickels. She has a total of 28 coins. how many of each type of coin does she have?
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Answer:

11 dimes, 17 nickels

Step-by-step explanation:

d + n = 28, put one variable by itself on a side, d = 28 - n

.10d + .05n = 1.95

Sub the first equation into the second

.10(28 - n) + .05n = 1.95

2.8 - .10n + .05n = 1.95

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7 0
2 years ago
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find the angle between the vectors. (first find the exact expression and then approximate to the nearest degree. ) a=[1,2,-2]. B
SashulF [63]

Answer:

\theta = cos^{-1} (\frac{10}{\sqrt{9} \sqrt{25}})=cos^{-1} (\frac{10}{15}) = cos^{-1} (\frac{2}{3}) = 48.190

Since the angle between the two vectors is not 180 or 0 degrees we can conclude that are not parallel

And the anfle is approximately \theta \approx 48

Step-by-step explanation:

For this case first we need to calculate the dot product of the vectors, and after this if the dot product is not equal to 0 we can calculate the angle between the two vectors in order to see if there are parallel or not.

a=[1,2,-2], b=[4,0,-3,]

The dot product on this case is:

a b= (1)*(4) + (2)*(0)+ (-2)*(-3)=10

Since the dot product is not equal to zero then the two vectors are not orthogonal.

Now we can calculate the magnitude of each vector like this:

|a|= \sqrt{(1)^2 +(2)^2 +(-2)^2}=\sqrt{9} =3

|b| =\sqrt{(4)^2 +(0)^2 +(-3)^2}=\sqrt{25}= 5

And finally we can calculate the angle between the vectors like this:

cos \theta = \frac{ab}{|a| |b|}

And the angle is given by:

\theta = cos^{-1} (\frac{ab}{|a| |b|})

If we replace we got:

\theta = cos^{-1} (\frac{10}{\sqrt{9} \sqrt{25}})=cos^{-1} (\frac{10}{15}) = cos^{-1} (\frac{2}{3}) = 48.190

Since the angle between the two vectors is not 180 or 0 degrees we can conclude that are not parallel

And the anfle is approximately \theta \approx 48

3 0
3 years ago
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