Lets O is the center of the circle and Lets A is a point cut on CD from O
mCD = m<COD
OA is perpendicular bisector of CD so OA = 1/2 CD = 1/2(12.7) = 6.35
Sin (DOA) = AD/OD = 6.35 / 9.06
Sin DOA = 0.7009
<DOA = 44.5°
<COD = 2 x 44.5°
<COD = 89°
mCD = <COD = 89°
Answer: 89°
Answer:
n to the power of 2
Step-by-step explanation:
baiscally just subtract 6-4 to get 2
9514 1404 393
Answer:
40°
Step-by-step explanation:
The sum of arcs of a circle is 360°, so the measure of arc CD is ...
CB +BD +CD = 360°
CD = 360° -140° -140° = 80°
The measure of inscribed angle B is half the measure of the arc it subtends:
∠B = arc CD/2 = 80°/2
∠B = 40°
