Answer:
Red = 10 cm, blue = 14 cm
Step-by-step explanation:
<em>Let the length of each red rod be </em><em>r </em><em>and each blue rod be </em><em>b</em>
<u>Then we have:</u>
<u>Multiply the first equation by 3 and the second one by 2:</u>
<u>Add the equations to eliminate one of variables:</u>
<u>Find the value of b:</u>
- 3*10 -2b = 2
- 30 - 2 = 2b
- 2b = 28
- b = 14 cm
Answer:
x=2
Step-by-step explanation:
We know AC = BC since this is an isosceles triangle
6 = 2x+2
Subtract 2 from each side
6-2 =2x+2-2
4 =2x
Divide each side by 2
4/2 =2x/2
2=x
Answer:
A) 68.33%
B) (234, 298)
Step-by-step explanation:
We have that the mean is 266 days (m) and the standard deviation is 16 days (sd), so we are asked:
A. P (250 x < 282)
P ((x1 - m) / sd < x < (x2 - m) / sd)
P ((250 - 266) / 16 < x < (282 - 266) / 16)
P (- 1 < z < 1)
P (z < 1) - P (-1 < z)
If we look in the normal distribution table we have to:
P (-1 < z) = 0.1587
P (z < 1) = 0.8413
replacing
0.8413 - 0.1587 = 0.6833
The percentage of pregnancies last between 250 and 282 days is 68.33%
B. We apply the experimental formula of 68-95-99.7
For middle 95% it is:
(m - 2 * sd, m + 2 * sd)
Thus,
m - 2 * sd <x <m + 2 * sd
we replace
266 - 2 * 16 <x <266 + 2 * 16
234 <x <298
That is, the interval would be (234, 298)
if you are looking for.... 2(B-4)= (6)b
2b - 8 = 6b
2b - 6b= 8
-4b=8
so b= -2
the question is b-4 divided by 6 equals b/2