Question

An airline finds that about 8 percent of the time, a person who makes an advance reservation does not keep the reservation. Therefore, for each of their 105105105-passenger planes, the company schedules 113113113 people with advance reservations. Based on this information, about how many of the scheduled people will not keep their reservation?

Answer 1

Answer:

about 9 passengers will not keep theire reservation

Step-by-step explanation:

given that an airline finds that about 8 percent of the time, a person who makes an advance reservation does not keep the reservation

Capacity of the airline per trip = 105 only

But company schedules = 113 people with advance reservations

Since 8% do not turn up

out of 113 passengers who reserved in advance we can say

that 8% of 113 passengers will not keep their reservation

Based on this information, number  of the scheduled people will not keep their reservation

= $8%of 113\\= \frac{8*113}{100} \\=9.04$

Since persons cannot be in decimals we can expect about 9 passengers will not keep theire reservation