Answer: For three traits inherited in a dominant/recessive pattern, the probability of an offspring in a trihybrid cross between parents heterozygous for all three traits to be recessive at exactly two of the three loci is 23/64.
Explanation: Let A, B and C represent the dominant alleles and a, b and c represent the recessive alleles. The genotype of each of the parent will be AaBbCc since it has been said to be heterozygous for all the three traits. There are eight (8) possible different types of gametes from each of the genotype. This can be calculated using 2^n where n is the number of heterozygous loci.
The number of heterozygous loci in the genotype AaBbCc is three (3). 2^3 = 8. The gametes are;
ABC
ABc
AbC
Abc
aBC
aBc
abC and
abc.
Therefore, sixty-four possible offsprings are expected from the cross AaBbCc x AaBbCc.
Out of these offsprings, twenty-three (23) are expected to be heterozygous at two loci as boldly shown in the attached image.
Answer:
Water is Polar
Explanation:
There is no overall charge to a water molecule, but there is a slight positive charge on each hydrogen atom and slight negative charge on the oxygen atom.
Explanation:
The tick carries harmful bacteria that was released into Charlie's blood.
So, I can conclude that:
tick> indirect, bacteria direct
Hope this helped! Let me know if this is incorrect.
Answer:
i) Glucose
ii) β(1-4) glycosidic bonds.
iii) Oxygen
Explanation:
Cellulose is an important structural carbohydrate found in plants. It forms a major component of the plant cell wall.
Cellulose is a polysaccharide formed by monomers of glucose. These glucose monomers are joined together by covalent bonds called β(1-4) glycosidic bonds, which means that the 1st carbon of one glucose is bound to the 4th carbon of the next glucose. To make this arrangement, every other glucose molecule in cellulose is inverted, which you can see in the diagram.
Glucose monomers contain carbon, hydrogen, and oxygen only. If you look at the pattern of the molecule (remembering every second glucose is inverted), you can see that Z must be O.
The functional group denoted by Z is oxygen. The OH groups on the glucose from one cellulose chain form hydrogen bonds with oxygen atoms on the same or on another chain, holding the chains firmly together and forming very strong molecules - giving cellulose its strength.
