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denpristay [2]
3 years ago
7

Surface area of a cylinder radius is 2 and height is 3

Mathematics
1 answer:
Lerok [7]3 years ago
6 0

Answer:

62.83 cm squared

Step-by-step explanation:

A = 2πrh+2πr^2

A = 2π(2)(3)+2π(2)^2

A = 2π(6)+2π4

A = 12π+8π

A = 20π

A = 20(3.14)

A = 62.83 cm squared

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Simplify the expression 3x + 14x + 35 + 2
IRINA_888 [86]

Answer:

17x + 37

Step-by-step explanation:

looked it up

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3 years ago
The resistance for resistors of a certain type is a random variable Xhaving the normal distribution with mean 9 ohms and standar
Y_Kistochka [10]

Answer:

P(8.6

And using the normal standard distirbution or excel we got:

P(-1

Step-by-step explanation:

Let X the random variable that represent the resistance for resistors of a population, and for this case we know the distribution for X is given by:

X \sim N(9,0.4)  

Where \mu=9 and \sigma=0.4

We are interested on this probability

P(8.6

And the z score formula is given by:

z=\frac{x-\mu}{\sigma}

Using this formula we got:

P(8.6

And using the normal standard distirbution or excel we got:

P(-1

3 0
3 years ago
Read 2 more answers
Find a & b if the point p(6,4)&q(2,3) lie on the graph of ax+by=20
Cerrena [4.2K]

Answer:

a = - 2 , b = 8

Step-by-step explanation:

Since the points p and q lie on the graph then they satisfy the equation

(6, 4 ) , substitute x = 6 , y = 4 into the equation

6a + 4b = 20 → (1)

(2, 3 ) , substitute x = 2, y = 3 into the equation

2a + 3b = 20 → (2)

Multiplying (2) by - 3 and adding to (1) will eliminate a

- 6a - 9b = - 60 → (3)

add (1) and (3) term by term to eliminate a

0 - 5b = - 40

- 5b = - 40 ( divide both sides by - 5 )

b = 8

Substitute b = 8 into either of the 2 equations and solve for a

Substituting into (1)

6a + 4(8) = 20

6a + 32 = 20 ( subtract 32 from both sides )

6a = - 12 ( divide both sides by 6 )

a = - 2

4 0
3 years ago
Read 2 more answers
What are the solutions of the equation x4 + 3x2 + 2 = 0? Use u substitution to solve. x = plus-or-minus i StartRoot 2 EndRoot an
Rom4ik [11]

Answer:

x=\pm\sqrt{2}i\text{ (or) }x=\pm i

Step-by-step explanation:

We have been given an equation x^4 + 3x^2 + 2 = 0. We are asked to find the solutions of our given equation using u-substitution.

We can rewrite our given equation as:  

(x^2)^2+3x^2+2 = 0

Let us assume that u=x^2.

u^2+3u+2 = 0

u^2+2u+u+2 = 0

u(u+2)+1(u+2) = 0

(u+2)(u+1) = 0

(u+2)=0\text{ (or) }(u+1) = 0

u=-2\text{ (or) }u=-1

Upon substituting back the value of u, we will get:

x^2=-2\text{ (or) }x^2=-1

x=\pm\sqrt{-2}\text{ (or) }x=\pm\sqrt{-1}

x=\pm\sqrt{-1\cdot 2}\text{ (or) }x=\pm\sqrt{-1}

Now we will use imaginary unit i. We know that i^2=-1.

x=\pm\sqrt{i^2\cdot 2}\text{ (or) }x=\pm\sqrt{i^2}

x=\pm\sqrt{2}i\text{ (or) }x=\pm i

Therefore, the solutions for our given equation are x=\pm\sqrt{2}i\text{ (or) }x=\pm i.

5 0
3 years ago
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STatiana [176]

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l ^ 2 + l ^ 2 = x ^ 2

Where:

l: It's the side of the square.

2l ^ 2 = x ^ 2\\l ^ 2 = \frac {x ^ 2} {2}

We know that the area of a square is given by:

A = l ^ 2

So, the area is:

A = \frac {x ^ 2} {2}

Answer:

A = \frac {x ^ 2} {2}

8 0
3 years ago
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